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Mrrafil [7]
2 years ago
6

The sum of two numbers is 56. the sum of the smaller and 5 times the larger is 192. find the numbers.

Mathematics
1 answer:
Kamila [148]2 years ago
3 0

Let the numbers = x,y

x+y = 56      1st eqn

x+5y = 192   2nd eqn

56-y+5y = 192

4y = 136

y = 34

substitute that in 1st eqn, x = 56-34 = 22

So, smaller number = 22 & Larger number = 34



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A set of numbers satisfies Benford’s Law if the probability of a number starting with digit d is P(d) = log(d + 1) – log(d).
irakobra [83]

Interpreting the graph and the situation, it is found that the values of d that can be included in the solution set are 1 and 4.

----------------------

  • According to Benford's law, the probability of a number starting with digit is d is:

P(d) = \log{(d + 1}} - \log{d}

  • A number can start with 10 possible digits, ranging from 1 to 9, which are all integer digits.
  • Thus, d can only assume integer digits.
  • In the graph, the solution is d < 5.
  • The integer options for values of d are 1 and 4.
  • For the other options that are less than 5, they are not integers, so d cannot assume those values.

A similar problem is given at brainly.com/question/16764162

8 0
2 years ago
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Identify the function as a power function, a polynomial function, or neither.<br><br> f(x)=4(x^3)^3
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Answer:7

Step-by-step explanation:7

7 0
3 years ago
Please answer this question now
lidiya [134]

Answer:

C = (2,2)

Step-by-step explanation:

B = (10 ; 2)

M = (6 ; 2)

C = (x ; y )

|___________|___________|

B (10;2)            M (6;2)             C ( x; y)

So:

dBM = dMC

√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 6)^2]

(2-2)^2 - (6-10)^2 = (y-2)^2 + (x - 6)^2

0 + (-4)^2 = (y-2)^2 + (x - 6)^2

16 = (y-2)^2 + (x - 6)^2

16 - (x - 6)^2 = (y-2)^2

Also:

2*dBM = dBC

2*√[(2-2)^2 + (6-10)^2] = √[(y-2)^2 + (x - 10)^2]

4*[(0)^2 + (-4)^2] = (y-2)^2 + (x - 10)^2

4*(16) = (y-2)^2 + (x - 10)^2

64 = (y-2)^2 + (x - 10)^2

64 = 16 - (x - 6)^2 + (x - 10)^2

48 = (x - 10)^2 - (x - 6)^2

48 = x^2 - 20*x + 100 - x^2 + 12*x - 36

48 = - 20*x + 100 + 12*x - 36

8*x = 16

x = 2

Thus:

16 - (x - 6)^2 = (y-2)^2

16 - (2 - 6)^2 = (y-2)^2

16 - (-4)^2 = (y-2)^2

16 - 16 = (y-2)^2

0 =  (y-2)^2

0 = y - 2

2 = y

⇒ C = (2,2)

4 0
3 years ago
Someone please help with this asap!! I will mark brainliest if it's right! Serious answers only !!!
Arlecino [84]

Answer:

1) given

2) given

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Step-by-step explanation:

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Lady bird [3.3K]

Answer:

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Step-by-step explanation:

sing the equation         >    A  =  Pe^rt

20000  =    10000e^0.1t    >       10%  =  0.1

2  = e^0.1t

log 2  =    log e^0.1t               >     log to the base e

log 2  =  0.1t * 1              log e to the base e  =1

0.6931 = 0.1t

t =   6.931

  =    7 years

Hope this helps <3

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3 years ago
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