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2 years ago

Can somebody plz help answer both these word problems and (write amp equation for each problem and solve) thx :3

Mathematics

1 answer:

soldi70 [24.7K]2 years ago

8 0

Answer:

14. She deposited $15.50 into her bank.

15. The width would be 900.

Step-by-step explanation:

14. 245.60 + x = 261.10

x = 15.50

245.60 + 15.50 = 261.10.

She deposited $15.50 into her bank and resulted in her new bank balance appearing as $261.10.

15. Width is 900 cm

Length is 12 cm.

A = L X W = 108

A = L * 3/4L

108 = 3/4L2

Divide both sides by 3/4: multiply both sides by the inverse of 3/4 or 4/3.

(4/3)*108 = L2

144 = L2

√144 = L

12 = L

W = 3/4*12

W = 9

Before we finish:

A = 108 = 9 x 12 = 108

W/L = 3/4 = 9/12 = 3/4

The width of the rectangle would be 3/4.

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3 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

2 years ago