The answer is True, those items are essential for working with hazardous chemicals.
12 grams of methane is one mole. So there are N(Avogadro)=6.22 x 10^23 molecules in one mole of methane
The given reaction is:
H2(g) + CO2(g) → H2O(g) + CO(g)
i.e.
H-H + O=C=O → H-O-H + C≡O
Reaction enthalpy (ΔH) is given as:
ΔH = ∑ΔH(Bonds broken) + ∑ΔH(Bonds formed)
= [1*ΔH(H-H) + 2*ΔH(C=O)] + [2*ΔH(O-H) + 1*ΔH(C≡O)]
=[+436 +2(799)] + [2(-463) +1(-1072)] = 36 kJ/mol
The enthalpy change for the given reaction is 36 kJ/mol
Answer:
<h2>2.4 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula
From the question we have
We have the final answer as
<h3>2.4 g/cm³</h3>
Hope this helps you
Hello There!
<span>Formed when two or more atoms chemically bond together, the resulting compound is unique both chemically and physically from its parent atoms</span>
Hope This Helps You!
Good Luck :)
- Hannah ❤