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igomit [66]
3 years ago
5

1. Your annual salary is $73, 300 and get paid bi-weekly. You are married and

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
3 0
Fnfnf kenzie said i had trttttttttt
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WHAT IS 1+1 <br><br><br> If u get it right tell me;) good luck
ella [17]

Answer:

4

Step-by-step explanation:

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4 0
3 years ago
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What are the restrictions for a? 2a^2+a-15/5a^2+16a+3
koban [17]

ANSWER


The restrictions are

a\ne -3,a\ne -\frac{1}{5}


EXPLANATION


We were given the rational function,


\frac{2a^2+a-15}{5a^2+16a+3}


The function is defined for all values of a, except



5a^2+16a+3=0


This has become a quadratic trinomial, so we need to split the middle term.


We do that by multiplying the coefficient of x^2 which is 5 by the constant term which is 3. This gives us 15.


The factors of 15 that adds up to 16 are 1 and 15.


We use these factors to split the middle term.




5a^2+15a+a+3=0


We now factor to get,


5a(a+3)+1(a+3)=0


We factor further to get,


(a+3)(5a+1)=0



This implies that,


(a+3)=0,(5a+1)=0


This gives


a=-3,a=-\frac{1}{5}


These are the restrictions.





8 0
3 years ago
Find the first five terms of the sequence given the following recursive formula:
forsale [732]

Answer:

The first five terms are;

-3,-7,11,-29,69

Step-by-step explanation:

The recursive definition of the sequence is

a_1=-3,, a_2=-7 and a_n=a_{n-2}-2a_{n-1}.

When n=3, we obtain;

a_3=a_{3-2}-2a_{3-1}.

\implies a_3=a_{1}-2a_{2}.

\implies a_3=-3-2(-7).

\implies a_3=11.

When n=4

\implies a_4=a_{2}-2a_{3}.

\implies a_4=-7-2(11)=-29.

When n=5

\implies a_5=a_{3}-2a_{4}.

\implies a_4=11-2(-29)=69.

Therefore the first five terms are;

-3,-7,11,-29,69

5 0
3 years ago
PLEASE HELP ME Given O below, if XY and YZ are congruent, what is the measure of YOZ
boyakko [2]

Answer:

140°

Step-by-step explanation:

1. full the circle is 360°;

2. YZ+XY=360-80; ⇔ YZ+XY=280;

3. if YZ=XY, then YZ=XY=280/2=140, ⇒ YOZ=140°

4 0
3 years ago
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HELP ASAP HELP PLEASE ASAP
Zinaida [17]
No no no no no no no no no
5 0
3 years ago
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