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Bogdan [553]
3 years ago
13

Evaluate this expression, be sure to use the correct order to calculate. 6* (5+6) ​

Mathematics
1 answer:
sattari [20]3 years ago
6 0

Answer:

66

u in first grade??

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What is the value of F in the formula F=9/5C+32 when C=30?
kherson [118]
I don't know i think is C
8 0
3 years ago
Read 2 more answers
A random sample of 64 bags of white cheddar popcorn weighed, on average, 5.23 ounces with a standard deviation of 0.24 ounce.
emmasim [6.3K]

Answer:

We conclude that cheddar popcorn weighed less than 5.5 ounces.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ =5.5 ounces

Sample mean, \bar{x} = 5.23 ounces

Sample size, n = 64

Alpha, α = 0.05

Sample standard deviation, σ = 0.24 ounce.

First, we design the null and the alternate hypothesis

H_{0}: \mu = 5.5\text{ ounces}\\H_A: \mu < 5.5\text{ ounces}

We use One-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{5.23 - 5.5}{\frac{0.24}{\sqrt{64}} } = -9

Now, z_{critical} \text{ at 0.05 level of significance } =-1.645

Since,  

z_{stat} < z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that cheddar popcorn weighed less than 5.5 ounces.

3 0
4 years ago
11.(02.03)
Marianna [84]

Answer:

step number 1 is incorrect.

Step-by-step explanation:

Here is the solution of this equation [2x-31-1=2].

2x-31-1=2

or 2x-31=2+1

or 2x=2+1+31

or 2x= 34

or x=34/2

or x= 17

the answer of this equation is X=17.

8 0
3 years ago
Find the median of the data in the box plot below.
Bumek [7]

Answer:

Median = 6.5 or 6 1/2

HOPE THIS HELPED! HAVE A GREAT DAY! :)

5 0
4 years ago
Solve the system of elimination -2x+2y+3z=0 -2x-y+z=-3 2x+3y+3z=5
Dahasolnce [82]

Answer:

x = 1 , y = 1 and z = 0

Step-by-step explanation:

-2x+2y+3z=0    ------(1)

-2x-y+z=-3     --------(2)

2x+3y+3z=5    ---------(3)

<u>To find the values of x,y and z</u>

(3) - (2)⇒ 2y + 4z = 2

y + 2z = 1   --------(4)

(1) - (2)⇒ 3y +2z =3   ---(5)

(5) - (4)⇒ 2y = 2

y = 1

Substituting the value of y in (4) we get z =0

Substituting the value of y and z  in (1) we get x = 1

Therefore x = 1 , y = 1 and z = 0

5 0
4 years ago
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