Answer:
The numbers are -14,-13 and -12
Step-by-step explanation:
<u><em>The correct question is </em></u>
Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?
Let
x ----> the first consecutive integer
x+1 ---> the second consecutive integer
x+2 ---> the third consecutive integer
we have that

solve for x
apply distributive property

Combine like terms

subtract 8 both sides


Divide by 6 both sides

so


therefore
The numbers are -14,-13 and -12
Answer:
0.79
Step-by-step explanation:
i calvulated and got 0.79
The answer to your question is 1
Explanation: negative divided by a negative is a positive
Answer:
(2 decimal places)
Step-by-step explanation:
Quadratic Formula: 
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Plug in values:

First value of x:
(2 decimal places)
Second value of x:
(2 decimal places)
You would distribute the 3a to the other terms inside the parenthesis:
3a*8a=24a^2
3a*(-6b)=-18ab
Your answer would be 24a^2-18ab