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Lunna [17]
3 years ago
6

PLEASE HELP ME!!!! 20 POINTS!!!!!!!

Mathematics
1 answer:
hammer [34]3 years ago
5 0
I think it’s B hope this helps
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An artifact is discovered at a certain site. if it has 59% of the carbon-14 it originally contained, what is the approximate age
Lapatulllka [165]
0.59  = (1 - 0.000125)^^x    where x =  number of years of decay

ln 0.59  = x ln(0.999875)

x = 4221  to nearest year
5 0
4 years ago
If the measure of 0 is A radians and B degrees, then A=180B/pie
yKpoI14uk [10]
Yup that is correct, that is the way to convert measurements of angle from radians to degrees. because 2pi is equivalent to one revolution of a circle and in degrees is equal to 360 degrees, then simplifying it 360 / 2pi = 180 / pi.
so <span>the measure of 0 is A radians and B degrees, then A = 180 B/pi</span>
3 0
3 years ago
Help anyone<br> 8th grade math?
Kruka [31]

Answer: x = 1

Step-by-step explanation:

2.8 + 2x = 0.6 x 8

2.8 x + 2x = 4.8

2x = 4.8 - 2.8 (subtract 2.8 on both sides)

2x = 2

x = 1 (divide 2 on both sides)

Hope this helps

7 0
3 years ago
Read 2 more answers
To solve y and x, I am adding a picture
Viktor [21]

Answer:

x =\sqrt 5

y = \sqrt{5

Step-by-step explanation:

Given

The attached triangle

Required

Solve for x

Considering angle 45 degrees, we have:

\cos(45) = \frac{y}{\sqrt{10}} --- cosine formula i.e. adj/hyp

Solve for y

y = \sqrt{10} * \cos(45)

In radical form, we have:

y = \sqrt{10} * \frac{1}{\sqrt 2}

y = \sqrt{10/2}

y = \sqrt{5

To solve for x, we make use of Pythagoras theorem

x^2 + y^2 = (\sqrt{10})^2

x^2 + y^2 =10

Substitute for y

x^2 + (\sqrt 5)^2 =10

x^2 + 5 =10

Collect like terms

x^2  =10-5

x^2=   5

Solve for x

x =\sqrt 5

4 0
3 years ago
A certain isotope decays so that the amount A remaining after t years is given by: A = A0 · e ^-0.03t where A0 is the original a
Katena32 [7]
<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k  (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187 </span>
about 23 years
</span></span>
7 0
3 years ago
Read 2 more answers
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