Answer:
I think you wrote something wrong.
Step-by-step explanation:
If Alaina has $7 in her bank account and Joel had $48 in his Joel already has more then Alaina but I will attempt to teach you how to solve these types of problems.
for this example I'm giving Alaina 79 dollars.
First we know were starting with 79 dollars and increasing 6 dollars each day so the equation for this is; y = 6x + 79 that is Alaina's equation.
For Joel our equation will be; y = 8x + 48.
Since they already have 79 and 48 dollars in their bank we put those as our B in the equation cause they are our y-intercepts. (Y = mx + b) Next we know their increasing by 6 and 8 dollars a day so we make those our m. Once we have these equations we can plot them and see where the lines meet. (thats our answer) I plotted them on desmos graphing calculator.
They crossed at (15.5, 172) Which means it will take 16 days for Joel to catch up they will both have 172 dollars in the bank account on the 16th day.
Hope this helps!
Answer:
10 losses
Step-by-step explanation:
Here, we want to get the greatest possible number of games the team lost
Let the number of games won be x
Number drawn be y
Number lost be z
Mathematically;
x + y + z = 38
Let’s now work with the points
3(x) + 1(y) + z(0) = 80
3x + y = 80
So we have two equations here;
x + y + z = 80
3x + y = 80
The greatest possible number of games lost will minimize both the number of games won and the number of games drawn
We can have the following possible combinations of draws and wins;
26-2
25-5
24-8
23-11
22-14
21-17
21-17 is the highest possible to give a loss of zero
Subtracting each sum from 38, we have the following loses:
10, 8, 6, 4, 2 and 0
This shows the greatest possible number of games lost is 10
D
C
Sorry if both aren't correct, it's been a while since i did this...
