Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
"the following" of what? I think you are missing the list
Answer:
B.
Step-by-step explanation:
The absolute value of 0 is 0 so 0 = 0 is true.
3,503,832.97 hope this helps! :)
Answer:
The common difference is -20
Step-by-step explanation:
Simply subtract 5 from -15
-15-5 = -20
