Let the difference between consecutive terms be D. If the middle term is 30, then the term before it is 30-D, and the term after it is 30+D. So the sum of these three terms would be (30-D) + 30 + (30+D) = 3*30.
Extending this sum to include all 11 terms centered around 30, we see that any addition of D is canceled by a balanced subtraction, leaving you with 11 copies of 30. So the value of the sum is 11*30 = 330.
Answer:
The answer is 22.
Step-by-step explanation:
6x+2x+4=180
8x+4=180
8x=176
x=22
49.5-40 = 9.5
so 40 x 8.18 = 327.20
8.18 x 1.5 = 12.27
12.27 x 9.5 = 116.57
327.20 + 116.57 = $443.77
1)
log 98 = log( 7 * 14 ) = log 7+ log 14= h + j ;
2)
log 175 = log ( 5^2 * 7 ) = log 5 ^ 2 + log 7 = 2 * log 5 + log 7 = 2i + h ;
3)
log 2 = log ( 14 / 7 ) = log 14 - log 7 = j - h ;
4)
log 245 = log ( 7^2 * 5 ) = log 7 ^2 + log 5 = 2 * log 7 + log 5 = 2h + i ;
Answer:
Step-by-step explanation:
the 2 friend eat 5/8
