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Ainat [17]
2 years ago
14

Please helpp a. what's the domain and range of c

Mathematics
1 answer:
lord [1]2 years ago
7 0

Answer:

range is 8 id k about domain

Step-by-step explanation:

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Where on a number line are the numbers x for which <br><br>|x|&gt;1
Andrews [41]

Answer:

Step-by-step explanation:

Given the inequality

|x|> 1

The modulus of x shows that x can be both positive and negative value.

If x is positive:

x>1

1<x

If x is negative:

-x>1

Multiplying both sides of the inequality by minus will change the inequality sign

x < -1

Combining both inequalities:

1<x<-1

Find the position on the number line in the attachment

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3 years ago
What happens to a figure that is dilated by a factor of 13
USPshnik [31]

Answer: it gets smaller, 13 times smaller

Step-by-step explanation:

Size of the figure/13

7 0
2 years ago
Y= 16t (squared) +120 what is t
Zina [86]

Answer:

Step-by-step explanation:

hello :

16t²+120 = y

16t² = y -120   so : t² = (y-120)/16

if  :  y-120 ≥ 0        t = ±√((y-120)/16)

5 0
3 years ago
carl wants to buy a television that costs $500, including taxes. To pay for the television, he will use a payment plan that requ
agasfer [191]
<span>The payment plan requires him to make a down payment of $125, and then pay $72.50 each month for 6 months. The total payment would be: $125 + 6*$72.50= $125 + $435= $560

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8 0
3 years ago
Read 2 more answers
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
Read 2 more answers
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