3.3 hope this helps thanks
$1.30. You can take the two statements and make them into equations. First set X equal to the number of dimes and Y equal to the number of quarters. Next set up your equations. the first .1X times .25Y=4.55 and X=Y. Next use substitution to solve for X, and you get 13. Next multiply 13 times .1 to get 1.3 which is in dollars.
![f(x)=x^3](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E3)
![g(x)=(x-2)^3 + 7](https://tex.z-dn.net/?f=g%28x%29%3D%28x-2%29%5E3%20%2B%207)
The +7 means we shift f up 7 units.
The -2 means what was f(0) before is g(2) so we're shifting f 2 units to the right to get g.
Answer: Incorrect, Gia switched left and right
Answer:
Step-by-step explanation:
From the given rectangle,
Length of the rectangle = 5 cm
Width of the rectangle = 10 cm
Ratio of length : width = 1 : 2
Perimeter of the rectangle = 2(l + b)= 150 cm
l + b = 75 -----(1)
Since, l : b = 1 : 2
b = 2l ------(2)
From equations (1) and (2),
l + 2l = 75
3l = 75
l = 25 m
Width 'b' = 2(25) = 50 m
Now we have to draw a rectangle with a scale = 25 : 2
Therefore, Scale factor = ![\frac{25}{l}=\frac{25}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B25%7D%7Bl%7D%3D%5Cfrac%7B25%7D%7B2%7D)
l = 2 cm
Similarly,
![\frac{50}{w}=\frac{25}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B50%7D%7Bw%7D%3D%5Cfrac%7B25%7D%7B2%7D)
w = 4 cm
Now we can draw a rectangle with length = 2 cm and width = 4 cm.
A=6a^2 is how you solve the surface area of a cube