Answer:
there are 4 bathroom towels per basket
Step-by-step explanation:
the equation is 16/4=4 hope this helps :)
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way
Step-by-step explanation:
- From a standard deck of cards, one card is drawn. What is the probability that the card is black and a
jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
- A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen
or an ace.
P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13
- WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces?
P(AA) = (4/52)(3/51) = 1/221.
- WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king?
P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed.
- WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the
probability of drawing the first queen which is 4/52.
- The probability of drawing the second queen is also 4/52 and the third is 4/52.
- We multiply these three individual probabilities together to get P(QQQ) =
- P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
- Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
Answer:
- Question 1a. i)
- Question 1a. ii)
- Question 1b)
Explanation:
<u><em>Question 1 a. i) Find the value of x.</em></u>
For the smalll triangle you can write:
For tthe big triangle:
Substitute:
Solve for x:
<u><em>Question 1a ii) Find the volume of the frustrum</em></u>
- Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m
Formula:
Substitute:
- Find the volume of a cone with heigth = 1.8m and radius = 1m
- Subtract the volume of the small cone from the volume of the big cone
<u><em>Question 1b. Calculate the volume of the bin</em></u>
<u>i) Upper frustrum</u>
This is the same frustrum from the equation of above, thus ist volume is 27.6m³.
<u>ii) Lower frustrum</u>
<u>iii) Add the volume of the two frustrums</u>
The weight of a shipment of 2560 balls weighs 320 pounds.
<h3>
How much would a shipment of 2560 tennis balls weigh?</h3>
We know that 24 tennis balls weigh 3 pounds. Then the weight of a single tennis ball is:
W = (3 lb)/(24 balls) = (1/8) pounds per ball.
To get the weight of 2560 tennis balls, we just need to multiply the number of tennis balls by the weight of a single ball, then we get:
Total weight = 2560*(1/8) pounds per ball = 320 pounds.
The weight of a shipment of 2560 balls weighs 320 pounds.
If you want to learn more about weight:
brainly.com/question/25973294
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