If gravity had no effect on a ball after you threw it ... and there also
were no air to slow it down ... then the ball would continue traveling
in a straight line, in whatever direction you threw it.
That's the heart and soul of Newton's laws of motion ... any object
keeps moving at the same speed, and in a straight line in the same
direction, until a force acts on it to change its speed or direction.\
If you threw the ball horizontally, then it would keep moving in the
same direction you threw it. But don't forget: The Earth is not flat.
The Earth is a sphere. So, as the ball kept going farther and farther
in the same straight line, the Earth would curve away from it, and it
would look like the ball is getting farther and farther from the ground.
<h2>
Answer:</h2>
The <u>interstellar medium</u> is the content of matter and energy that exists between stars within a galaxy.
In this sense, two components can be distinguished in the interstellar medium: dust particles and gas.
Dust represents 1% of the interstellar medium in mass, while the gas (consisting mainly of hydrogen and helium) represents 99% of the mass of the interstellar medium.
It should be noted that the interstellar matter is not uniformly distributed but is concentrated in molecular clouds.
I think it’s the Full Moon
Answer:
55.28 m
Explanation:
Mass of the rocket = 950 g = 950 / 1000 = 0.95 kg
force of gravity = 0.95 Kg × 9.81 m/s² = 9.3195 N
force due to acceleration = 18.3 N - 9.3195 N = 8.9805 N
F = ma
acceleration of the rocket = F / m = 8.9805 N / 0.95 Kg = 9.45 m/s²
using the equation of motion
d = ut + 1/2 at² u = 0 m/s
d = 1/2 at²
t = √(2d / a) = √ ( 2 × 40 m / 9.45 m/s²) = 2.91 s
the horizontal distance between the target and the rocket = vt = 19 m/s × 2.91 s = 55.28 m
Answer:
Explanation:
The east vector is 10cos45 = 7.07 km
The north vector is 10sin45 - 10 = -2.93 km
The displacement magnitude is
d = √(7.07² + 2.93²) = 7.65... = 8 km
θ = arctan(-2.93/7.07) = -22.51... = 23° south of east.
