Law of universal gravitation:
F = GMm/r²
F = gravitational force, G = gravitational constant, M & m = masses of the objects, r = distance between the objects
F is proportional to both M and m:
F ∝ M, F ∝ m
F is proportional to the inverse square of r:
F ∝ 1/r²
Calculate the scaling factor of F due to the change in M:
k₁ = 2M/M = 2
Calculate the scaling factor of F due to the change in m:
k₂ = 2m/m = 2
Calculate the scaling factor of F due to the change in r:
k₃ = 1/(4r/r)² = 1/16
Multiply the original force F by the scaling factors to obtain the new force:
Fk₁k₂k₃
= F(2)(2)(1/16)
= F/4
<span>Technician a says that to prevent injuries in an auto accident, all steering columns have a break-off steering wheel. technician b says that to prevent injuries in an accident, all steering columns are now fitted with a flexible rubber tube. Both technicians are correct. The </span>vehicle manufacturers use break away steering column mounting brackets to protect the driver in an accident. The <span>vehicle manufacturers are required to use collapsible shafts in the steering column. </span>
I have read that it is enough energy to power the needs of civilization for an entire year.
Hi there, your question was incomplete, so I will be solving a similar question so it would help you to understand how to answer these types of questions
Q) A chemist must dilute 22.5mL of 119μ M aqueous silver(II) oxide AgO solution until the concentration falls to 65.0μ M . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Round your answer to significant digits.
Answer:
<u>Final Volume V2 = 41.2 mL</u>
Explanation:
We will start by first recalling the formula of dilution which goes by,
M1 * V1 = M2 * V2 ------------------------------(1)
Now let us consider V1 = 22.5 mL
M1 = 119μ M
M2 = 65.0μ M
lets substitute the values above in equation 1,
M1 * V1 = M2 * V2
V2 = (M1 * V1)/M2 ( I have created V2 as the subject here)
V2 = (119*22.5)/65
<u>V2 = 41.2 mL</u>