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jolli1 [7]
3 years ago
15

A nonuniform electric field is directed along the x-axis at all points in space. This magnitude of

Physics
1 answer:
vagabundo [1.1K]3 years ago
7 0

Answer:

E) -0.28 nC

Explanation:

For using Gauss law

we calculate flux through whole cylinder.

  • On curved part flux is zero
  • On left par flux is =-\pi *0.1^{2} 2000= -20*\pi
  • On right par flux is =-\pi *0.1^{2} 1000= 10*\pi

    Total flux =-10\pi

According to Gauss law

net flux along closed surface=  \int\limits^a_b {E} \, ds=\frac{charge enclosed}{epsilon}[epsilon =8.85 *10^{-12}]

 10\pi=\frac{q enclosed}{epsilon}

plug in the values

we get charge enclosed = -0.28 nC

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According to Ohm's law, a circuit with a high resistance _____. will have a low electric current will have a high electric curre
lyudmila [28]
Remark
When you are asked a question like this, the first thing to do is search out a formula and put some limits on it.

Formula
I = E/R which comes from E = IR. To get to the derived formula, divide both sides by R
E/R = I*R/R
E/R = I

Discussion
This is an inverse relationship. That means that as one goes up the other one will go down. 

So in this case you keep E constant and you manipulate R and look at your results for I

Case 1

Let us say that E = 10 volts
Let us also say the R = 10 ohms

I = E/R
I = 10/10
I = 1 ohm

Case Two
Let's raise the Resistance to 100 ohms
E = 10
R = 100
I = 10/100 = 0.1 

Conclusion
As the Resistance goes up, the current goes down. Answer: A
8 0
3 years ago
Read 2 more answers
A sled of mass 10 kg slides along the ice. it has an initial speed of 2 m/s but stops because of friction. How much work is done
NeX [460]

Answer: The correct answer is option B.

Explanation:

Mass of the sled = 10 kg

Initial speed of the sled = 2 m/s

Kinetic energy of the sled = \frac{1}{2}mv^2

\frac{1}{2}\times 10 kg\times (2 m/s)^2=20 Joules

Work done by the sled = 20 joules

The work done by the friction will be in opposite direction and equal to the magnitude of the work done of the sled that - 20 J.

Hence, correct answer is option B.

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3 years ago
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calculate the diameter of a silver wire of length 75cm , which is extended by 1.85mm when a 10kg mass is suspended from it's end
sdas [7]

Answer:0.8\ mm

Explanation:

Given

length of wire l=75\ cm

change in length \Delta l=1.85\ mm

mass of wire m=10\ kg

Young's modulus for silver E=7.9\times 10^{10}\ N/m^2

load on wire F=mg

F=10\times 9.8=98\ kg

change in length is given by

\Delta l=\dfrac{Pl}{AE}

Where A=area of cross-section

A=\dfrac{Pl}{\Delta lE}

A=\dfrac{98\times 0.75}{1.85\times 10^{-3}\times 7.9\times 10^{10}}

A=\dfrac{73.5}{14.615\times 10^{7}}

A=5.029\times 10^{-7}\ m^2

also wire is the shape of cylinder so cross-section is given by

A=\dfrac{\pi d^2}{4}=5.029\times 10^{-7}\ m^2

\Rightarrow d^2=\dfrac{5.029\times 10^{-7}\times 4}{\pi }

\Rightarrow d^2=64.02\times 10^{-8}

\Rightarrow d=8\times 10^{-4}\ m

\Rightarrow d=0.8\ mm

4 0
3 years ago
Which term s the product of force and distance?
goldfiish [28.3K]

Answer:

The answer should be <u>WORK </u>

<em>(Hope this Helps)</em>

Explanation:

work is equal to the product of force and distance.

W=F*S

W=Work

F=Force applied

S=Distance

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Tor F: When you exert a force on a baseball, the equal and opposite force on the
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The answer would be false
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