Answer:
There needs to be an odd number of 1 bits
Explanation:
In memory, parity checking method is used to test the memory. There are two parity conditions. Either the parity is even or the parity is odd.
Odd parity means, number of 1's in eight bits of data. If the number 1's are odd it means parity is odd. In case of the memory testing result the parity should be odd.
So, In case of Parity of RAM, the parity should be odd, if the data is stored in the RAM.
Why are you asking other people to answer a question about something that's affected <u>you?</u>
Answer:
Multimeter
Explanation:
A multimeter or multitester or VOM (volt-ohm-milliammeter), is a tool to measure electricity and this tool has some function to measure voltage, current, and resistance. We could find analog and digital multimeters, and we can find expensive certificates and professionals multimeters ($5,000) or cheap ($10).
Answer:
#include<iostream>
using namespace std;
int lcm(int m, int n) {
int a;
a = (m > n) ? m: n;
while (true) {
if (a % m == 0 && a % n == 0)
return a;
++a;
}
}
int gcd(int m, int n) {
int r = 0, a, b;
a = (m > n) ? m : n;
b = (m < n) ? m : n;
r = b;
while (a % b != 0) {
r = a % b;
a = b;
b = r;
}
return r;
}
int main(int argc, char **argv) {
cout << "Enter the two numbers: ";
int m, n;
cin >> m >> n;
cout << "The LCM of two numbers is: " << lcm(m, n) << endl;
cout << "The GCD of two numbers is: " << gcd(m, n) << endl;
return 0;
}
Explanation:
Coding works through programming/programs. Programs have different coding languages, and text files. The code within the file is known as the "source CODE" this code is used in different ways, causing for the possibility of separate binary files that computers can directly run. Hope I helped.
