Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
Answer:
i think its 130
Step-by-step explanation:
hope this helps? :|
Multiply
2
2
by
5
5
.
x
5
+
10
x
4
+
10
x
3
⋅
2
2
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
10
x
3
⋅
2
2
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
Raise
2
2
to the power of
2
2
.
x
5
+
10
x
4
+
10
x
3
⋅
4
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
10
x
3
⋅
4
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
Multiply
4
4
by
10
10
.
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
2
3
+
5
x
⋅
2
4
+
2
5
Raise
2
2
to the power of
3
3
.
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
8
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
40
x
3
+
10
x
2
⋅
8
+
5
x
⋅
2
4
+
2
5
Multiply
8
8
by
10
10
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
2
4
+
2
5
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
2
4
+
2
5
Raise
2
2
to the power of
4
4
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
16
+
2
5
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
5
x
⋅
16
+
2
5
Multiply
16
16
by
5
5
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
80
x
+
2
5
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
80
x
+
2
5
Raise
2
2
to the power of
5
5
.
x
5
+
10
x
4
+
40
x
3
+
80
x
2
+
80
x
+
32
Answer:
a
Step-by-step explanation:
answer
Answer:
d
Step-by-step explanation:
