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Margarita [4]
3 years ago
14

In the following figure lines j and k are parallel and are cut by transversal t Thanks

Mathematics
1 answer:
Sedbober [7]3 years ago
4 0

angle 1 and angle 7 are alternate exterior angles.

angle 1 and angle 5 are corresponding angles.

angle 3 and angle 8 are same side interior angles.

angle 2 and angle 8 are alternate interior angles.

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Betty is canning 104 pears and 126 apples separately. Each jar holds 8 pears or 6 apples. How many jars does Betty need
Nina [5.8K]
For the pears, Betty will need 13 jars. I know this because I divided 104 by 8. I did the same for the apples. 126 divided by 6. You get 21. Have a nice day!
8 0
4 years ago
Help last question I’ll tell y’all my score!
Rudiy27

Answer:

15

Step-by-step explanation:

graph shows

postcards=15

shirts=10

pencils= 40

we're going to add postcards and shirts THEN comparing it to pencils

postcards and shirts=15+10= 25

pencils= 40

answer=40-25=15

5 0
3 years ago
One container of dried cherries costs $7. How many containers can you buy for $14?
Vilka [71]
7x2=14
So the answer would be 2
6 0
4 years ago
Read 2 more answers
Rx - sx + y = b solve for y
daser333 [38]

Answer:

y =  b-rx+sx

Step-by-step explanation:

rx - sx + y = b

Subtract rx from each side

rx-rx - sx + y = b-rx

-sx +y = b-rx

Add sx to each side

sx - sx + y = b-rx+sx

y =  b-rx+sx

3 0
3 years ago
How many ten-digit numbers have at least two equal digits?
hammer [34]

Answer:

8,996,734,079 numbers

Step-by-step explanation:

First let's find the number of ten-digit numbers.

The maximum ten-digit number is 9,999,999,999 and the minimum is 1,000,000,000. So the number of ten-digit numbers is:

N(total) = 9999999999 - 1000000000 = 8,999,999,999

Now, to find the number of ten-digit numbers with at least two equal digits, we can find the number of ten-digit numbers with all digits different, and then subtract this amount from the total ten-digit numbers.

To find the number of ten-digit numbers with all digits different, we can use the following logic:

The first digit can have 9 different values (0 not included), the second can also have 9 (one digit used), then the third can have 8 (two digits used), the fourth can have 7, and so on. So we have that:

N(different) = 9*9! = 3,265,920

Then the number of ten-digit numbers with at least two equal digits is:

N(two\ equal) = N(total)-N(different) = 8999999999 - 3265920

N(two\ equal) = 8,996,734,079

3 0
3 years ago
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