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jek_recluse [69]
3 years ago
13

X^2+18x−29=−10 A. x=−4±√29 B. x=5±√86 C. x=−1±2√14 D. x=1, x=−19

Mathematics
1 answer:
baherus [9]3 years ago
4 0

Answer:

answer is d.)x=1 , x= -19

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PLEASE HELP ASAP……..
bogdanovich [222]

Answer:

4x+2y = 14  The original equation

2y = 14-4x  Subtract 4x from both sides

2y = -4x+14  Rearrange so x is first

y = -2x+7  Divide everything by 2

Explanation:

The steps above practically explain everything needed, so there's not much to add. The standard form is Ax+By = C while slope intercept form is y = mx+b

In the case of y = -2x+7, we have a slope of m = -2 and y intercept of b = 7. This means (0,7) is one point on the line. Use the slope to move down two and to the right one unit to arrive at (1, 5) as another point on this line.

7 0
1 year ago
35 (t + 29) = −3(3 − t)
Olin [163]

Answer: -32

Step-by-step explanation:

35 (t + 29) = −3(3 − t)

Open the brackets

35t+1015= -9+3t

Collect like terms

35t-3t=-9-1015

32t= -1024

Divide both side by 32

32t/32 = -1024/32

t= -32

8 0
4 years ago
Read 2 more answers
What does 24 divided by 1.5 equal.
choli [55]
16 would be the answer
3 0
3 years ago
Read 2 more answers
2 plez!!!?!?!?!?!?!?!?!??!!??!?!?!!??!?!?! I can’t figure it out I’ve tried everything it’s due tomorrow AHAHAHAH
harkovskaia [24]
So to do this one, you have to do the problem backwards!

The equation looks like this with everything plugged in:

272.2 = 2(3.14)r

You are looking for r, so start dividing

272.2 = 2(3.14)r
136.1 = (3.14)r
43.3 = r

Therefore the radius is about 43.3 in.

I hope I helped!
5 0
3 years ago
Is the given point interior, exterior, or on the circle (x + 2)2 + (y - 3)2 = 81? P(8, 4)
Elodia [21]
From the equation we see that the center of the circle is at (-2,3) and the radius is 9.

So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...

d^2=(8--2)^2+(4-3)^2  and d^2=r^2=81 so

81=10^2+1^2

81=101  which is not true...

So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.  

Thus the point lies outside or on the exterior of the circle...
8 0
3 years ago
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