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zvonat [6]
3 years ago
15

I don’t know how much she need to make

Mathematics
1 answer:
Ivanshal [37]3 years ago
7 0

Answer:

4

Step-by-step explanation:

She can make 4. Have an amazing day

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Hello everyone, need help on this, select all the correct answers that are equivalent.
mihalych1998 [28]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

You can perform the division and look at the quotient and remainder to convert an improper fraction to a mixed number.

  23 ÷ 6 = 3 r 5   ⇒   23/6 = 3 5/6 ≠ 4 1/6

  11 ÷ 4 = 2 r 3   ⇒   11/4 = 2 3/4 ≠ 2 1/2

  35 ÷ 4 = 8 r 3   ⇒   35/4 = 8 3/4

  15 ÷ 8 = 1 r 7   ⇒   15/8 = 1 7/8

  40 ÷ 12 = 3 r 4   ⇒   40/12 = 3 4/12 = 3 1/3

5 0
2 years ago
Find the product 7/10 x 3/6 (please help!) fractions​
hichkok12 [17]

Answer:

7/10 x 3/6 = 21/60

21/60 in its simpliest form =  7/20

5 0
10 months ago
Read 2 more answers
Ken bakes several batches of cookies throughout the day for his bakery. He records the number of cookies, in dozens, that are in
lina2011 [118]
<h3>✽ - - - - - - - - - - - - - - -  ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ The equation would have to be y = 4/3 x + 4 because the y intercept is 4 and the gradient is positive.

The two correct statements are the first and last ones.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

3 0
2 years ago
Find the center of a circle with the equation: x2 y2−32x−60y 1122=0 x 2 y 2 − 32 x − 60 y 1122 = 0
mixas84 [53]

The equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

The center of the circle exists at (16, 30).

<h3>What is the equation of a circle?</h3>

Let, the equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

We rewrite the equation and set them equal :

$(x-h)^2 + (y-k)^2 - r^2 = x^2+y^2- 32x - 60y +1122=0

$x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = x^2 + y^2 - 32x - 60y +1122 = 0

We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.

-2hx = -32x

h = -32/-2

⇒ h = 16.

-2ky = -60y

k = -60/-2

⇒ k = 30.

The center of the circle exists at (16, 30).

To learn more about center of the circle refer to:

brainly.com/question/10633821

#SPJ4

7 0
1 year ago
The solution set for -2x^2+12x=0
natita [175]

Answer:

{0,6}

Step-by-step explanation:

-2x^2+12x = 0

Factor out a -2x

-2x(x-6) =0

Using the zero product property

-2x = 0   and x-6=0

-2x = 0

Divide by -2

-2x/-2 = 0/-2

x=0  

x-6=0

Add 6 to each side

x-6+6 =0+6

x=6

The solutions are 0 and 6

7 0
2 years ago
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