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BigorU [14]
3 years ago
11

X+2 1/3 = 2. find the value of x in the equation​

Mathematics
1 answer:
Llana [10]3 years ago
8 0

Answer:

X=1 1/3

Step-by-step explanation:

X+2 1/3=2

X=2-2 1/3

X=4/3

X=1 1/3

Hope this is useful to u

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Could you explain how you got the answer to please
Zina [86]

Answer:

I think is 53 A

Step-by-step explanation:

6 0
3 years ago
Suppose the number of messages that an inbox receives may be modeled by a Poisson distribution. If the average number of message
docker41 [41]

Answer:

0.36427

Step-by-step explanation:

Mean = λ = 18 messages per hour

P(X = x) = (e^-λ)(λ⁻ˣ)/x!

P(X ≤ x) = Σ (e^-λ)(λ⁻ˣ)/x! (Summation From 0 to x)

But the probability required is that the messages thay come in an hour is between 15 and 20, that is, P(15 < X < 20)

P(15 < X < 20) = P(X < 20) - P(X ≤ 15)

These probabilities will be evaluated using a cumulative frequency calculator.

P(X < 20) = 0.65092

P(X ≤ 15) = poissoncdf(18, 15) = 0.28665

P(15 < X < 20) = P(X < 20) - P(X ≤ 15) = 0.65092 - 0.28665 = 0.36427.

You can use the Poisson distribution calculator here

https://stattrek.com/online-calculator/poisson.aspx

4 0
3 years ago
5b^2+3b-4 how do I find (x,y)?
GrogVix [38]

Answer:

DONT TRUST THE LINK OF OTHER USER AND REPORT

5 0
3 years ago
ASAP!!!<br> Find the zero of the function f(x) = -8x + 4.<br> a. -1/2<br> b. 2<br> c. -2<br> d. 1/2
Katyanochek1 [597]

Answer:

D. 1/2

Step-by-step explanation:

Because if you choose A , you get +4

if you choose B ,you get -12

Choose C , you get +20

D is the correct answer.

6 0
3 years ago
The number of column inches of classified advertisements appearing on Mondays in a certain daily newspaper is normally distribut
lana66690 [7]

Answer:

The probability there will be between 280 and 360 column inches of classified advertisement

P(280≤X≤360) = P(-2≤Z≤2) = 0.9544

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean  the population = 320

The standard deviation of the Population = 20

Let 'X' be the random variable in a normal distribution

Let 'X' = 280

Z = \frac{x-mean}{S.D} = \frac{280-320}{20} = -2

Let 'X' = 360

Z = \frac{x-mean}{S.D} = \frac{360-320}{20} = 2

<u><em>Step(iii):-</em></u>

The probability there will be between 280 and 360 column inches of classified advertisement

P(280≤X≤360) = P(-2≤Z≤2)

                        = P(z≤2) -P(z≤-2)

                       = P(z≤2)+P(z≤2)

                      = 2P(z≤2)

                     = 2×0.4772     ( from normal table)

                    = 0.9544

6 0
3 years ago
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