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Serhud [2]
3 years ago
10

I was killed යඞ what do i do

Computers and Technology
1 answer:
KiRa [710]3 years ago
8 0
Answer:

Ok all you have to do is live if you died , very simple and basic anyone can do it
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The command line is a location <span>on your computer screen where you type text entries to communicate with the computer’s operating system.</span>
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This project must target a Unix platform and execute properly on our CS1 server.
sweet-ann [11.9K]

Answer:

hope this helps ,if it did pls do consider giving brainliest

Explanation:

// Java program for implementation of FCFS scheduling

import java.text.ParseException;

class GFG {

// Function to find the waiting time for all

// processes

static void findWaitingTime(int processes[], int n,

int bt[], int wt[]) {

// waiting time for first process is 0

wt[0] = 0;

// calculating waiting time

for (int i = 1; i < n; i++) {

wt[i] = bt[i - 1] + wt[i - 1];

}

}

// Function to calculate turn around time

static void findTurnAroundTime(int processes[], int n,

int bt[], int wt[], int tat[]) {

// calculating turnaround time by adding

// bt[i] + wt[i]

for (int i = 0; i < n; i++) {

tat[i] = bt[i] + wt[i];

}

}

//Function to calculate average time

static void findavgTime(int processes[], int n, int bt[]) {

int wt[] = new int[n], tat[] = new int[n];

int total_wt = 0, total_tat = 0;

//Function to find waiting time of all processes

findWaitingTime(processes, n, bt, wt);

//Function to find turn around time for all processes

findTurnAroundTime(processes, n, bt, wt, tat);

//Display processes along with all details

System.out.printf("Processes Burst time Waiting"

+" time Turn around time\n");

// Calculate total waiting time and total turn

// around time

for (int i = 0; i < n; i++) {

total_wt = total_wt + wt[i];

total_tat = total_tat + tat[i];

System.out.printf(" %d ", (i + 1));

System.out.printf(" %d ", bt[i]);

System.out.printf(" %d", wt[i]);

System.out.printf(" %d\n", tat[i]);

}

float s = (float)total_wt /(float) n;

int t = total_tat / n;

System.out.printf("Average waiting time = %f", s);

System.out.printf("\n");

System.out.printf("Average turn around time = %d ", t);

}

// Driver code

public static void main(String[] args) throws ParseException {

//process id's

int processes[] = {1, 2, 3};

int n = processes.length;

//Burst time of all processes

int burst_time[] = {10, 5, 8};

findavgTime(processes, n, burst_time);

}

}

// Java program to implement Shortest Job first with Arrival Time

import java.util.*;

class GFG {

static int[][] mat = new int[10][6];

static void arrangeArrival(int num, int[][] mat) {

for (int i = 0; i < num; i++) {

for (int j = 0; j < num - i - 1; j++) {

if (mat[j][1] > mat[j + 1][1]) {

for (int k = 0; k < 5; k++) {

int temp = mat[j][k];

mat[j][k] = mat[j + 1][k];

mat[j + 1][k] = temp;

}

}

}

}

}

static void completionTime(int num, int[][] mat) {

int temp, val = -1;

mat[0][3] = mat[0][1] + mat[0][2];

mat[0][5] = mat[0][3] - mat[0][1];

mat[0][4] = mat[0][5] - mat[0][2];

for (int i = 1; i < num; i++) {

temp = mat[i - 1][3];

int low = mat[i][2];

for (int j = i; j < num; j++) {

if (temp >= mat[j][1] && low >= mat[j][2]) {

low = mat[j][2];

val = j;

}

}

mat[val][3] = temp + mat[val][2];

mat[val][5] = mat[val][3] - mat[val][1];

mat[val][4] = mat[val][5] - mat[val][2];

for (int k = 0; k < 6; k++) {

int tem = mat[val][k];

mat[val][k] = mat[i][k];

mat[i][k] = tem;

}

}

}

// Driver Code

public static void main(String[] args) {

int num;

Scanner sc = new Scanner(System.in);

System.out.println("Enter number of Process: ");

num = sc.nextInt();

System.out.println("...Enter the process ID...");

for (int i = 0; i < num; i++) {

System.out.println("...Process " + (i + 1) + "...");

System.out.println("Enter Process Id: ");

mat[i][0] = sc.nextInt();

System.out.println("Enter Arrival Time: ");

mat[i][1] = sc.nextInt();

System.out.println("Enter Burst Time: ");

mat[i][2] = sc.nextInt();

}

System.out.println("Before Arrange...");

System.out.println("Process ID\tArrival Time\tBurst Time");

for (int i = 0; i < num; i++) {

System.out.printf("%d\t\t%d\t\t%d\n",

mat[i][0], mat[i][1], mat[i][2]);

}

arrangeArrival(num, mat);

completionTime(num, mat);

System.out.println("Final Result...");

System.out.println("Process ID\tArrival Time\tBurst" +

" Time\tWaiting Time\tTurnaround Time");

for (int i = 0; i < num; i++) {

System.out.printf("%d\t\t%d\t\t%d\t\t%d\t\t%d\n",

mat[i][0], mat[i][1], mat[i][2], mat[i][4], mat[i][5]);

}

sc.close();

}

}

7 0
3 years ago
What is displayed in the alert dialog box after the following code is executed? var items = 3; for (var i = 1; i &lt;= items; i+
LenKa [72]

Answer:

The factorial of 3=6

Explanation:

Following are the description of the given question

  • This is JavaScript code .Here items are the variable that are holding the integer value "3".
  • After that there is 2 loop are iterating one is outer and one inner loop.
  • When i=1 1<=3 the condition of outer loop is true  the control moves the inner loop .
  • In the inner loop there is variable result that is initialized by 1 Now checking the condition of inner loop j=i i.e j=1 1>=1 condition of inner loop is true it executed the statement inside the inner loop  so result =1 .Now we increment the value of i of the outer loop.
  • i=2 2<=3 the condition of outer loop is true  the control moves the inner loop .
  • In the inner loop there is variable result that is initialized by 1 Now checking the condition of inner loop j=i i.e j=2 2>=1 condition of inner loop is true it executed the statement inside the inner loop  so result =2 .Now we increment the value of i of the outer loop.
  • Now i=3 3<=3 the condition of outer loop is true  the control moves the inner loop .
  • In the inner loop there is variable result that is initialized by 1 Now checking the condition of inner loop j=i i.e j=3 3>=1 condition of inner loop is true it executed the statement inside the inner loop  so result =6 .Now we increment the value of i of the outer loop.
  • i=4 4<=3 the condition of outer loop is false  the control moves from  the outer loop.
  • It print The factorial of 3=6

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What are the OSHA construction standards also called ?
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Part 1926 & Part 1910


hope this helps 

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public colleges are cheaper for in-state residents

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