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Crazy boy [7]
3 years ago
12

The moon is 2.4 x 10^5 miles from earth. Assume the speed of the fastest spacecraft is 3.6 x 10^4 miles per hour. How many hours

would it take this spacecraft to fly to the moon from earth
Mathematics
1 answer:
alexgriva [62]3 years ago
6 0

Answer:

t = 6.67 seconds

Step-by-step explanation:

Given that,

The distance of Moon from Earth, d=2.4\times 10^5\ miles

The speed of the spacecraft, v=3.6\times 10^4\ miles/hour

We need to find the time it take this spacecraft to fly to the moon from earth. Let the time is t.

We know that,

Speed = distance/time

t=\dfrac{d}{v}\\\\t=\dfrac{2.4\times 10^5}{3.6\times 10^4}\\\\t=6.67\ s

So, the required time is equal to 6.67 seconds.

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ElenaW [278]
29*2.4-36.5= 33.1 hrs before the freight train cought up.
5 0
3 years ago
If a^2+1/a^2=79 where (a>0), find the value of a^3 +1/a^3
Nastasia [14]

Note the binomial expansion,

(<em>a</em> + 1/<em>a</em>)³ = <em>a</em> ³ + 3<em>a</em> + 3/<em>a</em> + 1/<em>a</em> ³

so

<em>a</em> ³ + 1/<em>a</em> ³ = (<em>a</em> + 1/<em>a</em>)³ - 3 (<em>a</em> + 1/<em>a</em>)

Similarly,

(<em>a</em> + 1/<em>a</em>)² = <em>a</em> ² + 2 + 1/<em>a</em> ²

We're given <em>a</em> ² + 1/<em>a</em> ² = 79, so

(<em>a</em> + 1/<em>a</em>)² - 2 = 79

(<em>a</em> + 1/<em>a</em>)² = 81

<em>a</em> + 1/<em>a</em> = ±9

but <em>a</em> > 0, so we ignore the negative solution.

Then

<em>a</em> ³ + 1/<em>a</em> ³ = 9³ - 3×9 = 702

7 0
3 years ago
What is then answer -7÷(-7)
pashok25 [27]
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8 0
3 years ago
Solve for x<br> 3xy=w<br><br> please help
san4es73 [151]

Answer

x= w/3y

Step-by-step explanation:

to isolate x you divide each side by 3y, which results in x= w/3y

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5 0
3 years ago
Read 2 more answers
Sheila walks 3 miles in 9/10 of an hour. How fast does she walk per hour?
scoundrel [369]

Answer:

1 hours = 60 min

60 x 9/10 = 54 min

3 divided by 54 = 1/18

so she walks 1/18 miles per hour.

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7 0
3 years ago
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