Given Information:
Total cards = 108
Red cards = 25
yellow cards = 25
Blue cards = 25
Green cards = 25
Wild cards = 8
Required Information:
Probability that a hand will contain exactly two wild cards in a seven-hand game = ?
Answer:
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
Step-by-step explanation:
The required probability is given by
P = number of ways of interest/total number of ways
The total number of ways of dealing a seven-card hand is
₁₀₈C₇
We want to select exactly 2 wild cards and the total wild cards are 8 so the number of ways of this selection is
₈C₂
Since the game is seven-card hand, we have to get the number of ways to select remaining 5 cards out of (108 - 8 = 100) cards.
₁₀₀C₅
Therefore, the setup for this problem becomes
P = number of ways of interest/total number of ways
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
This is the required setup that we can type into our calculators to get the probability of exactly two wild cards in a seven-hand card game with 8 wild cards and 108 total cards.
It’s c and i know cause i got it right
Answer:
5×10⁻²
Step-by-step explanation:
- Move the decimal so there is one non-zero digit to the left of the decimal point.
- The number of decimal places you move will be the exponent on the 10. a. If the decimal is being moved to the right, the exponent will be negative.
b. If the decimal is being moved to the left, the exponent will be positive.
- Therefore. The answer is 5×10⁻²
10(N + 3)
= 10N + 30
Hence, the answer is A.
Answer: 11
Step-by-step explanation:
It is 11 because count from -6...
-6 = 0
-5 = 1
-4 = 2
-3 = 3
-2 = 4
-1 = 5
0 = 6
1 = 7
2 = 8
3 = 9
4 = 10
5 = 11
Hope this helpsand sorry if not
