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guajiro [1.7K]
3 years ago
12

The dot plot shows the number of touchdowns a football team scored in 10 games​

Mathematics
2 answers:
dem82 [27]3 years ago
8 0
I think the answer is B
Delvig [45]3 years ago
3 0

Answer:

Step-by-step explanation:

B. The data clustered from 0 to 2

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What is the total amount that Mathews bank will receive after lending him 8000 for four years
marysya [2.9K]

Answer:

32,000

Step-by-step explanation:

5 0
3 years ago
WIll Give brainly and 100 POINTS!
Svet_ta [14]

Answer:

A: 2x+1= -1/4x+3

7 0
3 years ago
X+2=2(2x-14) solve for x.
LekaFEV [45]

X =10.


First distribute the 2(2x-14) and get 4x-28.

x+2-4x-28. Subtract x from each side to get 2=3x-28.

Add 28 to both sides to equal 30=3x. Divide each side by 3 to get your final Answer, x=10.

3 0
3 years ago
Which value of x makes x-3/4 + 2/3=17/12 true?
Bingel [31]

Answer:

x = 3/2

Step-by-step explanation:

x- 3/4 + 2/3 = 17/12

x = 17/12 + 3/4 -2/3

x = 3/2

7 0
3 years ago
The age at which small breed dogs are fully housebroken follows a Normal distribution with mean ms = 6 months and standard devia
atroni [7]

Answer:

This measure is just 0.17 standard deviations from the mean, so we should not be surprised.

Step-by-step explanation:

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If the z-score is lower than -2, or higher than 2.5, the score of X is considered unusual.

Subtraction of normal variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

Let xS – xL represent the sampling distribution.

Mean s 6, means L 4. So

\mu = 6 - 4 = 2

Standard deviation s is 2.5, for L is 1.5. So

\sigma = \sqrt{2.5^2+1.5^2} = 2.915

Should we be surprised if the sample mean housebroken age for the small breed dogs is at least 2.5 months more than the sample mean housebroken age for the large breed dogs? Explain your answer.

We have to find the z-score for X = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.5 - 2}{2.915}

Z = 0.17

This measure is just 0.17 standard deviations from the mean, so we should not be surprised.

7 0
2 years ago
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