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3 years ago

Find the value of x -14- POINTS

Mathematics

1 answer:

Zina [86]3 years ago

3 0

Answer:

Step-by-step explanation:

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What value of y satisfies the system of equations below?<br> 2x - y = 6<br> 2x + 3y = 14

Oksana_A [137]

Answer: y=2

Step-by-step explanation:

2x+3y=14 - 2x-y=6 = 4y=8

y=2

If you need x, just insert y into the equation and work out x from there

2x-2=6

2x=8

x=4

5 0

3 years ago

The explicit rule for a sequence is an=5(−2)^n−1

Murrr4er [49]

Answer:

3) $a_n=-2a_{n-1}$ , $a_1=5$

Step-by-step explanation:

Given that the explicit rule for a sequence is $a_n=5(-2)^{n-1}$ .

Now we need to find about what is the recursive rule for the sequence and match with the given choices to find the correct choice.

1) $a_n=-2a_{n+1}$ , $a_1=5$

2) $a_n=-5a_{n+1}$ , $a_1=2$

3) $a_n=-2a_{n-1}$ , $a_1=5$

4) $a_n=-5a_{n-1}$ , $a_1=2$

Plug n=1 into given formula to get first term

$a_n=5(-2)^{n-1}$

$a_1=5(-2)^{1-1}=5(-2)^{0}=5(1)=5$

base of the exponent part is (-2) so that means we need to multiply -2 to the previous term to get nth term

Hence correct choice is: 3) $a_n=-2a_{n-1}$ , $a_1=5$

7 0

3 years ago

Factor the expression completely.

evablogger [386]

Answer:

Factoring the expression $xy^4+x^4y^4$ completely we get $\mathbf{xy^4(x+1)(x^2-x+1)}$

Step-by-step explanation:

We need to factor the expression $xy^4+x^4y^4$ completely

We need to find common terms in the expression.

Looking at the expression, we get $xy^4$ is common in both terms, so we can write:

$xy^4+x^4y^4\\=xy^4(1+x^3)$

So, taking out the common expression we get: $xy^4(1+x^3)$

Now, we can factor the term (1+x^3) or we can write (x^3+1) by using formula:

$a^3+b^3=(a+b)(a^2-ab+b^2)$

So, we get:

$xy^4(1+x^3)\\=xy^4(x^3+1)\\Applying\:the\:formula\;of\:a^3+b^3\\=xy^4(x+1)(x^2-x+1)$

Therefor factoring the expression $xy^4+x^4y^4$ completely we get $\mathbf{xy^4(x+1)(x^2-x+1)}$

6 0

3 years ago

Find the value of k such that lim-->4 (x^2+x-k)/(x-4) exists

7nadin3 [17]

Answer:

k=20

Step-by-step explanation:

when x approaches 4, the denominator x-4 approaches 0

if the denominator is 0, it means that this is invalid

if the function is a number over 0 when x=4, it represents a vertical asymptote, which means no limit

so the only way possible to let there be a limit is to let the function be 0/0 when we plug in x=4

so x^2 + x - k = 0 when x = 4

4^2 + 4 - k = 0 ==> 20 - k = 0 ==> k = 20

6 0

3 years ago

5547x94<br> what is the answer

Veseljchak [2.6K]

Answer:

521418

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers