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2 years ago

One card is selected at random from a deck of cards.

Mathematics

1 answer:

Usimov [2.4K]2 years ago

6 0

Answer:

Probability that it is a red card: 50%

Probability that it is a black card: 50%

Step-by-step explanation:

You have an even probability of getting a red card or a black card. This is true because there are an even number of red cards and black cards. (25 or 26 of each, depending on if you include jokers.) Therefore, there is an even probability of getting a red card or a black card. It has to be 50%, because that is the only number in which two options can have equal numbers.

Hope this helps! :D

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lubasha [3.4K]

Answer:

- 6x² - 2x + 1

Step-by-step explanation:

Given

(2x³ - 4x² - 3x + 5) + (- 2x³ - 2x² + x - 4)

Both parenthesis are distributed by 1 thus just remove them

= 2x³ - 4x² - 3x + 5 - 2x³ - 2x² + x - 4 ← collect like terms

= - 6x² - 2x + 1

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3 years ago

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Diano4ka-milaya [45]

Answer:

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3 years ago

In Central City, Elm Street and Maple Street are parallel to one another. Oak Street crosses both Elm Street and Maple Street as

ycow [4]

a. true

b. false ( angles should equal 180 125+65=190)

c. true

d. true

e. true

5 0

3 years ago

Someone please explain I have zero clue how to answer this!

UkoKoshka [18]

Answer:

x=62

Step-by-step explanation:

152-90(because of the right angle)

the 28 is a red herring

4 0

3 years ago

Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least

Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

1) The probability of having a face card in the first turn

In this case, the chances are 12 in 52:

$P_1=P(face\, card)=12/52=0.231$

2) The probability of having a face card in the second turn, having a non-face card in the first turn.

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

$P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181$

3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141$

4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109$

With these four probabilities we can calculate the probability of losing this bet:

$P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662$

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

$P=P_1+P_2+P_3=0.231+0.181+0.141=0.553$

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0

3 years ago