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zalisa [80]
3 years ago
12

I'm taking a class in FLVS I finished segment 1 and I need to add another course for segment 2 and I don't know how to do that?

Please help
Mathematics
1 answer:
nlexa [21]3 years ago
5 0

Answer:

You could simply go to your course selection book (if there is one) and see if it's there. If not, then ask your guidance counselor for help or if you can automatically advance.

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Simplify 8 over negative 4 divided by negative 3 over 9. 6 −6 12 −12
skelet666 [1.2K]

Answer:

6

Step-by-step explanation:

Given

\frac{8}{-4} /  \frac{-3}{9}

Required

Solve

\frac{8}{-4} /  \frac{-3}{9}

We start by converting the division sign to multiplication

\frac{8}{-4} /  \frac{-3}{9} =\frac{8}{-4} *  \frac{-9}{3}

Then, we divide -9 by 3

\frac{8}{-4} /  \frac{-3}{9}=\frac{8}{-4} *  -3

Then, we divide 8 by -4

\frac{8}{-4} /  \frac{-3}{9}=-2 *  -3

Multiply -2 and -3 to give final result

\frac{8}{-4} /  \frac{-3}{9} = 6

Hence, \frac{8}{-4} /  \frac{-3}{9} is equivalent to 6

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3 years ago
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3 years ago
Read 2 more answers
25% of all who enters a race do not complete. 30 haveentered.
nikklg [1K]

Answer:

The probability that exactly 5 are unable to complete the  race is 0.1047

Step-by-step explanation:

We are given that 25% of all who enters a race do not complete.

30 have entered.

what is the probability that exactly 5 are unable to complete the  race?

So, We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

p is the probability of success i.e. 25% = 0.25

q is the probability of failure =  1- p  = 1-0.25 = 0.75

We are supposed to find the probability that exactly 5 are unable to complete the  race

n = 30

r = 5

P(X=5) =^{30}C_5 (0.25)^5 (0.75)^{30-5}

P(X=5) =\frac{30!}{5!(30-5)!} \times(0.25)^5 (0.75)^{30-5}

P(X=5) =0.1047

Hence the probability that exactly 5 are unable to complete the  race is 0.1047

6 0
3 years ago
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