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zalisa [80]
3 years ago
12

I'm taking a class in FLVS I finished segment 1 and I need to add another course for segment 2 and I don't know how to do that?

Please help
Mathematics
1 answer:
nlexa [21]3 years ago
5 0

Answer:

You could simply go to your course selection book (if there is one) and see if it's there. If not, then ask your guidance counselor for help or if you can automatically advance.

Step-by-step explanation:

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I dont know what to do for tis
kap26 [50]

Answer:

is this by any chance about simultaneous equations? If so,

Step-by-step explanation:

Step 1 is telling us to decide on whether x and y should be the unknown. For instance, you want x to be the unknown, so u solve for x.

Step 2 is telling us to write equations with x and y.

For example,

7x + 5y = 12

7x - 2y = 9

This may not be accurate but it is an equation.

Step 4 is telling us to check whether the solution is accurate or not. For instance, we say 7 is x. so we substitude 7 into the original equation to see whether the answer we found is correct.

For step 5, im not really sure.

hope this helps though???

5 0
2 years ago
Find the value of x.<br> 64<br> 100<br> XE
Tatiana [17]

Answer:

i think the answer should be 16

8 0
3 years ago
Heyy Answer please and explain
ludmilkaskok [199]

Answer: V=37.5 cm³

Step-by-step explanation:

Formula

V=(πr²h)/3

Given

r=5/2=2.5 cm

h=6 cm

Solve

V=(πr²h)/3

V=(π(2.5)²(6))/3

V=(π(6.25)(6))/3

V=37.5π/3

V=37.5(3)/3

V=37.5 cm³

Hope this helps!! :)

Please let me know if you have any questions

5 0
3 years ago
Determine whether the series is convergent or divergent by expressing sn as a telescoping sum (as in Example 8). [infinity] 6 n2
vekshin1

Answer:

Step-by-step explanation:

given

\sum\limits^\infty_{n=3}\frac{6}{n^2-1}=\sum\limits^\infty_{n=3}\frac{6}{(n-1)(n+1)}\\\\=\sum\limits^\infty_{n=3}\frac{6}{2}(\frac{1}{n-1}-\frac{1}{n+1})\\\\=\frac{6}{2}\sum\limits^\infty_{n=3}(\frac{1}{n-1}-\frac{1}{n+1})\\\\=3[(\frac{1}{2}-\frac{1}{4})+(\frac{1}{3}-\frac{1}{5})+(\frac{1}{4}-\frac{1}{6})+(\frac{1}{5}-\frac{1}{7})+...]\\\\=3[\frac{1}{2}+\frac{1}{3}]=3[\frac{3+2}{6}]=3[\frac{5}{6}]\\\\=\frac{15}{6}=\frac{5}{3}

5 0
3 years ago
What is 5 over 100 as a decimal
Alekssandra [29.7K]

Answer:

.05 im sure of it hope it helps.

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
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