If the area of each of the triangular regions is as shown, what is the area of the polygon?
1 answer:
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It is given that the triangle is isosceles right triangle . And in an isosceles right triangle the legs are equal . Let each leg be of x units. Now we use pythagorean identity, which is
So the length of each leg is
From any proportion, we get another proportion by inverting the extremes (or the means):
so we have:
2x=3k
2x+y=2k therefore:
3k+y=2k
y= - k
x=
The corect answer is A. -3/2
or:
From any proportion, we get another proportion by inverting the extremes and the means:
We use a property of proportions:
so we have
3y = - 2x
Answer: Please, see the attached file.
Thanks.
Solution:
We can graph using the intercepts:
(1) y-intercept, when x=0
y=4x-3→y=4(0)-3→y=0-3→y=-3
Point=(x,y)=(0,-3)
(2) x-intercept, when y=0
y=4x-3→0=4x-3
Solving for x: Adding 3 both sides of the equation:
0+3=4x-3+3
3=4x
Dividing both sides of the equation by 4:
3/4=4x/4
3/4=x
x=3/4=0.75
Point=(x,y)=(3/4,0)=(0.75,0)
With these pair of points (0, -3) and (0.75,0) we can draw the right line
