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Y_Kistochka [10]
3 years ago
5

Pls helppp thanks!!!

Mathematics
1 answer:
True [87]3 years ago
3 0

Answer:

64 inch³

Step-by-step explanation:

3 / 2 = 1.5 radius

1.5²x π x 10 = 22.5 π = volume

22.5 π x 9/10 = 20.25π of water

= 63.6172512352

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Elis [28]
It equals 16!!!!!!!!!!!
4 0
3 years ago
The lengths of the sides of a triangle are in the extended ratio 5: 8.9. The perimeter of the triangle is 44 cm. What are the le
max2010maxim [7]

Answer:

10cm, 16 cm, 18 cm

Step-by-step explanation:

We have to find the sum of proportion: sum of ratios =

a : b : c = 5:8:9

Sum of proportion = 5 + 8 + 9

= 22

Length of side a

5/22 × 44 = 10 cm

Length of side b

8/22 × 44 = 16 cm

Length of side a

9/22 × 44 = 18 cm

Therefore: lengths of the sides of the triangle in cm are

10cm, 16 cm, 18 cm

7 0
3 years ago
What is the “simple interest” earned if you invest $545 in a savings account that earns 3.25% for two years?
garri49 [273]

Answer:

The answer for this question is B)

3 0
4 years ago
A submarine was situated 800 feet below sea level.
Ghella [55]

Answer:

New position = -525 ft or 525 ft below the sea level

Step-by-step explanation:

Lets h be the height of the sea.

Given:

A submarine was situated 800 feet below sea level.

It is ascends 275 feet.

We know that h = 0 on the surface of the sea.

When we go below the surface vertically inside the sea the height will become negative.

So the submarine was situated h = -800 feet below the sea level, and it is ascends 275 feet from -800 feet.

So the new height of the submarine is.

h = -800 + 275

h = -525\ ft

Therefore the new position of the submarine is 525 below the sea level.

8 0
4 years ago
A contractor is building a new subdivision on the outside of a city. He has started work on the first street and is planning for
ruslelena [56]

You can use those two given points of street 1 to form its equation, then can use the fact that parallel lines have same slope to find the equation of second street with the help of the point (1,5) which lies in second street.

The equation of the location of the second street in standard form is given as 2y = x + 9

<h3>What is the equation of a straight line passing through two given points?</h3>

Let the two given points be (a,b) and (c,d). Then the equation of straight line passing through these two points is given by:

y - b = \dfrac{(d-b)}{(c-a)}(x-a)

<h3>What is slope intercept form of equation of straight line?</h3>

y = mx + c is the slope intercept form of straight line where m is the slope and c is the y-intercept (where the straight line cut on y = c at y axis) of the given line.

<h3>How to find equation of second street's location in terms of equation of straight line?</h3>

Firstly we will find the equation of straight line which represents street 1.

Since street 1 goes from point (-5,-6) and (3,-2), thus, its equation would be:

y - (-6) = \dfrac{-2- (-6)}{3-(-5)} (x -(-5))\\&#10;\\&#10;y + 6 = \dfrac{1}{2}(x+5)\\&#10;\\&#10;y + 6 = \dfrac{x}{2} + \dfrac{5}{2}\\\\&#10;y = \dfrac{x}{2} -\dfrac{7}{2}

Thus, this above equation represents equation of location of street 1. The slope is 1/2 and y-intercept is -7/2.

Since the street 2 is parallel to street 1, thus we have its slope same as that of street 1. Writing the equation in slope intercept form we get:

y = \dfrac{1}{2}x + c

Since street 2 passes through (1,5)( x=  1, y = 5), thus, this point must satisfy above equation which represents all points lying on street 2.

Thus,

5 = \dfrac{1}{2} \times 1 + c\\\\&#10;c = 5 - \dfrac{1}{2} = \dfrac{9}{2}

Thus, the equation representing points on street 2 is given by:

y = \dfrac{x}{2} + \dfrac{9}{2}\\&#10;\\&#10;2y = x + 9

Learn more about equation of straight line here:

brainly.com/question/19380936

7 0
2 years ago
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