Answer:
4(x - 
)² = 0
Step-by-step explanation:
Given
4x² - 4x + 1 = 0
To complete the square the coefficient of the x² term must be 1
Factor out 4 from 4x² - 4x
= 4(x² - x) + 1 = 0
add/subtract ( half the coefficient of the x- term )² to x² - x
4(x² + 2(- )x + 
- ) + 1 = 0
4(x - )² - 1 + 1 = 0
4(x - )² = 0
11. is 25°
(Both triangles have two congruent angles which means the 3rd angle is bound to be the same. Just add the 90° and the 65° to get 155 and subtract from 180° because all triangles equal 180°)
12. is 25°
(Same as before, two of the angles are congruent so the third one is the same. Add all of the angles together and have them equal 180° because their is a variable present. 2x+60+70=180 or 2x+130=180. subtract 130 from both sides to get the equation 2x=50 and then divide both sides by 2 to get x=25.)
13. y=14 and x=11.6 (assuming m<d says 15x ÷ 2 because I couldn't really read it)
(m<a = m<d and m<b = m<e because they are lined up together in the ABC and DEF equation. so 3y=42 and (15x÷2=87)
Answer:
Step-by-step explanation:
Area is the width (6/7 yd) multiplied by the height (1 yd).
6/7 x 1 = 6/7 
A vertical line that the graph of a function approaches but never intersects. The correct option is B.
<h3>When do we get vertical asymptote for a function?</h3>
Suppose that we have the function f(x) such that it is continuous for all input values < a or > a and have got the values of f(x) going to infinity or -ve infinity (from either side of x = a) as x goes near a, and is not defined at x = a, then at that point, there can be constructed a vertical line x = a and it will be called as vertical asymptote for f(x) at x = a
A vertical asymptote can be described as a vertical line that the graph of a function approaches but never intersects.
Hence, the correct option is B.
Learn more about Vertical Asymptotes:
brainly.com/question/2513623
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