PLZ HELP ME IM DUMB BC ITS FLIPPIN 12 IN THE MORNING> In a class where 65% of the students are girls, how boys are there if t
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Answer: There are 97 nickels and 108 quarters.
Step-by-step explanation:
Let x = Number of nickels, y = Number of quarters.
As per given,
x+y = 205 ...(i)
0.05x+0.25y = 31.85 ... (ii) [1 nickel = $0.05, 1 quarter = $ 0.25]
Multiply (ii) by 20, we get
x+5y=637 ...(iii)
Eliminate (i) from (iii)
4y = 432
⇒ y = 108 [Divide both sides by 4]
Put value of y in (i), we get
Hence, there are 97 nickels and 108 quarters.
For this case, the first thing we must do is define variables:
x: unknown number (1)
y: unknown number (2)
We now write the equations that model the problem:
their sum is 6.1:
their difference is 1.6:
Solving the system we have:
We add both equations:
Then, we look for the value of y using any of the equations:
Answer:
The numbers are:
x: unknown number (1)
y: unknown number (2)
We now write the equations that model the problem:
their sum is 6.1:
their difference is 1.6:
Solving the system we have:
We add both equations:
Then, we look for the value of y using any of the equations:
Answer:
The numbers are: