195 is between 100-200 and
195/5=39
195/3=65
But 195/4 is not a whole number the answer would be 48.75
So the number is 195. :)
There are two of them.
I don't know a mechanical way to 'solve' for them.
One can be found by trial and error:
x=0 . . . . . 2^0 = 1 . . . . . 4(0) = 0 . . . . . no, that doesn't work
x=1 . . . . . 2^1 = 2 . . . . . 4(1) = 4 . . . . . no, that doesn't work
x=2 . . . . . 2^2 = 4 . . . . . 4(2) = 8 . . . . . no, that doesn't work
x=3 . . . . . 2^3 = 8 . . . . . 4(3) = 12 . . . . no, that doesn't work
<em>x=4</em> . . . . . 2^4 = <em><u>16</u></em> . . . . 4(4) = <em><u>16</u></em> . . . . Yes ! That works ! yay !
For the other one, I constructed tables of values for 2^x and (4x)
in a spread sheet, then graphed them, and looked for the point
where the graphs of the two expressions cross.
The point is near, but not exactly, <em>x = 0.30990693...
</em>If there's a way to find an analytical expression for the value, it must involve
some esoteric kind of math operations that I didn't learn in high school or
engineering school, and which has thus far eluded me during my lengthy
residency in the college of hard knocks.<em> </em> If anybody out there has it, I'm
waiting with all ears.<em>
</em>
The first step would be :
E) 3x + (2x + 4) = -7
Since all the variables cancel out and the coefficient equal to eachother, this system of equation has
<u>infinitely many solutions!</u>
Answer:
y=1/4x+3
Step-by-step explanation:
To find the inverse, switch x and y or f(x)
f(x)=4x-12
y=4x-12
x=4y-12
Add 12 to both sides
x+12=4y-12+12
x+12=4y
Divide both sides by 4
x+12/4=y
1/4x+12/4=y
1/4x+3=y
y=1/4x+3
