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Nady [450]
3 years ago
11

What is the x value when g(x)=1 PLS HELP

Mathematics
1 answer:
olga_2 [115]3 years ago
3 0

Answer:

I believe the answer is x=1.

Step-by-step explanation:

I am a bit confused on what is wanted, but g(x) is the x value on the line g. so when g(x)=1, I think x=1 on the line g.

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Rectangle MNOP has diagonals NP and MO. Determine the length of NP if NP = 7x - 4 and MO = 3x + 19.
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Step-by-step explanation:

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3 years ago
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Verify that each equation is an identity (1 - sin^(2)((x)/(2)))/(1+sin^(2)((x)/(2)))= (1+cosx)/(3-cosX)
Allisa [31]

Answer:

Given that we have;

sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }

By the application of the law of indices and algebraic process of adding a and subtracting a fraction from a whole number, we have;

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) }  =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

Step-by-step explanation:

An identity is a valid or true equation for all variable values

The given equation is presented as follows;

\dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

From trigonometric identities, we have;

sin \left (\dfrac{x}{2} \right ) = \sqrt{\dfrac{1 - cos (x)}{2} }

\therefore sin^2 \left (\dfrac{x}{2} \right ) = \dfrac{1 - cos (x)}{2}

1 -  sin^2 \left (\dfrac{x}{2} \right ) = 1 - \dfrac{1 - cos (x)}{2} = \dfrac{2 - (1 - cos (x))}{2} = \dfrac{1 + cos (x))}{2}

1 +  sin^2 \left (\dfrac{x}{2} \right ) = 1 + \dfrac{1 - cos (x)}{2} = \dfrac{2 + 1 - cos (x))}{2} = \dfrac{3 - cos (x))}{2}

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( \dfrac{1 + cos (x)}{2} \right)}{\left (\dfrac{3 - cos (x)}{2} \right ) }  =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

\therefore \dfrac{\left ( 1 - sin^2 \left (\dfrac{x}{2} \right ) \right )}{\left ( 1 + sin^2 \left (\dfrac{x}{2} \right ) \right )} =\dfrac{\left ( 1 + cos (x))}{(3 - cos (x))}

3 0
3 years ago
What is 27% of 110,000?
Ket [755]
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4 0
4 years ago
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During a phone call, Beyunka was told of the most recent transactions in her company's business account. There were deposits of
Norma-Jean [14]

Answer:

The amount of change in the balance of the account is an increase of $3160.57.

Step-by-step explanation:

i) first deposit is given as $1250

ii) second deposit is given as $3040.57

iii) first withdrawal is given as $400

iv) second withdrawal is given as $400

v) third withdrawal is given as $400

vi) first penalty removed is $35

vii) second penalty removed is $35

viii) therefore the change to the balance is given by

$1250 + $3040.57 - $400 - $400 - $400 + $35 + $35 = $3160.57

viii) Therefore the amount of change in the balance of the account is an increase of $3160.57.

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3 years ago
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marshall27 [118]

Answer:          

     /\------------------------------\

a  /    \                                   \

 /        \                                   \ (Im not an artist....)

/_____ \________________\

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(A x B / 2) + (A x B / 2) + (A x C) + (A x C) + ( B x C) + (B x C)

Step-by-step explanation:

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