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3 years ago

15

Write an equation for the line that passes through the points (0, -6) and (-3, 0).

1 answer:

Dmitry [639]3 years ago

3 0

Answer:

$\displaystyle y = -2x -6$

Step-by-step explanation:

x-intercept → Plug in 0 for <em>y</em><em> </em>to get −3 for <em>x</em>

y-intercept → When <em>x</em><em> </em>is set equal to 0 [(0, −6)]

I am joyous to assist you anytime.

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4 years ago

What is the correct numeral form of this number written in scientific notation 1.5463 × 10 3

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3 years ago

F(x) = x2 + 3x + 2 is shifted 2 units left, the result is g(x). What is g(x)?

Veronika [31]

Answer:

$g(x)=x^2+7 x+12$

Step-by-step explanation:

since f(x)= $x^{2}+3 x+2$

now we are given that this function f(X) is shifted 2 units to the left and we get a function g(x) this means

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4 years ago

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SCORPION-xisa [38]

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3 years ago

Read 2 more answers

Please help me with both of these questions I’m supper stuck

Vitek1552 [10]

Answer:

ONE SOLUTION

Step-by-step explanation:

When two points on a line are given, the equation of the line is given by the formula:

$\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}$

where $(x_1, y_1)$ and $(x_2, y_2)$ are the points on the line.

Here, the first set of points are: $(-1, 3)$ and $(0, 1)$ .

Therefore, $(x_1, y_1) = (-1, 3)$ and $(x_2,y_2) = (0, 1)$ .

The line passing through this is given by:

$\frac{y - 3}{1 - 3} = \frac{x + 1}{1}$

$\implies y - 3 = -2x - 2$

∴ 2x + y - 1 =0

Now, for the second line, the points are:

$(x_1, y_1) = (1, 4)$ and $(x_2, y_2) = (0, 2)$ .

Therefore, $\frac{y - 4}{-2} = \frac{x - 1}{-1}$

$\implies -y + 4 = -2x + 2$

∴ 2x - y + 2 = 0

Now, to determine the number of solutions the two equations have, we solve these two equations,

Adding Eqn(1) and Eqn(2) we get:

4x = -1

$\implies x = \frac{-1}{4}$

And $y = \frac{3}{2}$ .

Since, we arrive at unique values of 'x' and 'y', we say the lines have only one unique solution.

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4 years ago