Answer:
The temperature of the gas in the 3.00 liter container, must be 150K
Explanation:
Let's apply the Ideal Gas Law, to find out the moles
P . V = n . R . T
1,20 atm . 5L = n . 0,082 L.atm/mol.K . 300 K
(1,20 atm . 5L) / (0,082 mol.K/L.atm . 300 K) = n
6/24,6 mol = n = 0,244 moles
We have the moles now, so let's find the temperature in our new conditions.
P . V = n . R . T
1 atm . 3L = 0,244 moles . 0,082 L.atm/mol.K . T° in K
(1 atm . 3L / 0,244 moles . 0,082 mol.K/L.atm) = T° in K
3/20,008 K = T° in K = 150K
