Answer:
0.294 M
Explanation:
The computation of the final molarity of acetate anion is shown below:-
Lead acetate = Pb(OAc)2
Lead acetate involves two acetate ion.
14.3 gm lead acetate = Mass ÷ Molar mass
= 14.3 g ÷ 325.29 g/mol
= 0.044 mole
Volume of solution = 300 ml.
then
Molarity of lead is
= 0.044 × 1,000 ÷ 300
= 0.147 M
Therefore the molarity of acetate anion is
= 2 × 0.147
= 0.294 M
Notice the subscript went from 83 to 84 and the 214 stayed the same that means it was beta decay.
Hydrogen. Covalent bonds occur within each linear strand and strongly bond the bases, sugars, and phosphate groups (both within each component and between components). Hydrogen bonds occur between the two strands and involve a base from one strand with a base from the second in complementary pairing.
Answer:
Two-electron.
Explanation:
Hello!
In this case, since the half-reaction by which chlorine is reduced to aqueous chloride ion is:
We can see each chlorine undergo a decrease of electrons by 1, it means that, since there are two chlorine atoms undergoing an electron decrease, we write:
Which means this is a two-electron process.
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