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Slav-nsk [51]
3 years ago
9

Which of the following represents the correct temperature and pressure at STP?

Chemistry
2 answers:
Natalija [7]3 years ago
4 0

Answer : The correct option is, (B) Temperature = 0^oC and Pressure = 1 atm

Explanation :

STP : STP stands for standard temperature and pressure.

At STP,

The temperature is, 0^oC or 32^oF

The pressure is, 1atm or 101.325kPa

The volume is, 22.4 L

Hence, the correct option is, (B) Temperature = 0^oC and Pressure = 1 atm

melamori03 [73]3 years ago
3 0
B is the correct answer if I remember
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A 27.3 g marble sliding to the right at 21.0 cm/s overtakes and collides with a 11.7 g marble moving in the same direction at 12
NISA [10]

Answer:

The answer to this is

The velocity of the 27.3Kg marble after collision is = 16.24 cm/s

Explanation:

To solve the question, let us list out the given variables and their values

Mass of first marble m1 = 27.3g

Velocity of the first marble v1 = 21.0 cm/s

Mass of second marble m2 = 11.7g

Velocity of the second marble v2 = 12.6 cm/s

After collision va1 = unknown and va2 = 23.7 cm/s

From Newton's second law of motion, force = rate of change of momentum produced

Hence m1v1 + m2v2 = m1va1 + m2va2 or

va1 = (m1v1 + m2v2 - m2va2)÷m2 or (720. 72-277.29)÷m1 → va1 = 16.24 cm/s

The velocity of the 27.3Kg marble after collision is = 16.24 cm/s

4 0
3 years ago
What does buffer do?? (Chemistry)​
pogonyaev
A buffer is a solution that can resist pH change upon the addition of an acidic or basic components. It is able to neutralize small amounts of added acid or base, thus maintaining the pH of the solution relatively stable. This is important for processes and/or reactions which require specific and stable pH ranges. Buffer solutions have a working pH range and capacity which dictate how much acid/base can be neutralized before pH changes, and the amount by which it will change.
4 0
2 years ago
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Part A Which acid in each of the following pairs has the stronger conjugate base? Match the words in the left column to the appr
vichka [17]

Answer:

HF

H₂S

H₂CO₃

NH₄⁺

Explanation:

<em>Which acid in each of the following pairs has the stronger conjugate base?</em>

According to Bronsted-Lowry acid-base theory, <em>the weaker an acid, the stronger its conjugate acid</em>. Especially for weak acids, pKa gives information about the strength of such acid. <em>The higher the pKa, the weaker the acid.</em>

<em />

  • Of the acids HCl or HF, the one with the stronger conjugate base is HF because it is a weak acid.
  • Of the acids H₂S or HNO₂, the one with the stronger conjugate base is    H₂S  because it is a weaker acid. pKa (H₂S) = 7.04 > pKa (HNO₂) = 3.39
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  • Of the acids HF or NH₄⁺, the one with the stronger conjugate base is NH₄⁺ because it is a weaker acid. pKa (HF) = 3.17 < pKa (NH₄⁺) = 9.25
6 0
2 years ago
HELP!
ki77a [65]

Answer:

(1)There are 1.5 moles of water in a 27 gram sample of water. The molar mass of water is 18.02 gmol g m o l .(2)

AnswersChemistryGCSEArticle

What is the mass (g) of 0.25mols of NaCl?

What you need for these equations are a calculator, periodic table and the following equation:

Mass (g) = Mr x Moles (important equation to remember)

In this case we already know the moles as it's in the question, 0.25 moles.

to find the Mr, you need to look at your periodic table. Find the relative atomic mass of Na and Cl and add the two numbers together.

Na = 22.99

Cl = 35.45

NaCl = 58.4

Now just put all of the numbers into the equation.

0.25 x 58.4 = 14.6g

4 0
3 years ago
Read 2 more answers
This is my chemistry worksheet. It's a new topic my teacher will barely review with us. Help please???
TEA [102]
So to balance an equation, you need to get the same amount of each type of element on either side of the --> . So you pretty much are given the subscripts in the equations and you need to add coefficients (just normal numbers) in front of any formula that needs it, keeping anything balance.
KCl_{3}  + O_{2}  -\ \textgreater \  KCl_{3}
turns into
2KCl_{3}+ 3O_{2} -> 2KCl_{3}

These coefficient numbers are the molar ratios, so 2 moles of KCl3 for every 3 moles of O2   so 1. 3:2

Then you can use these ratios of find out how many moles of one thing are needed if you are given the amount of another.
\frac{moles of element 1}{cofficient 1}  =  \frac{moles of element 2}{cofficient 2}
and use cross multiplication to solve for whatever you don't know


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