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mash [69]
2 years ago
15

Cell Phone Towers

Mathematics
1 answer:
Free_Kalibri [48]2 years ago
4 0
Part a
Is it to domsmsmmenemamsmmsne
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What is (f ° g)(2) and (g ° f)(2) with the set of points f: {(0,4), (1,2), (2,0), (3,2), (4,4)} and g: {(0,4), (1,3), (2,2), (3,
kumpel [21]

Answer:

\large\boxed{(f\circ g)(2)=0}\\\boxed{(g\circ f)(2)=4}

Step-by-step explanation:

f:\{(0,4), (1,2), \underline{(2,0)}, (3,2), (4,4)\}\\\\g:\{\underline{(0,4)}, (1,3), \underline{(2,2)}, (3,1), (4,0)\}\\\\(f\circ g)(x)=f\bigg(g(x)\bigg)\\\\g(2)=2\qquad/from\ (2,2)/\\f\bigg(g(2)\bigg)=f(2)=0\qquad/from\ (2,0)/\\\\(g\circ f)(x)=g\bigg(f(x)\bigg)\\\\f(2)=0\qquad/from\ (2,0)/\\g\bigg(f(2)\bigg)=g(0)=4\qquad/from\ (0,4)/

7 0
3 years ago
If A = 50 degrees, B = 62 degrees, and a = 4, find b.<br><br> Round to the nearest tenth.​
Phoenix [80]
<h3>Answer:  4.6</h3>

=================================================

Work Shown:

Use the law of sines

b/sin(B) = a/sin(A)

b/sin(62) = 4/sin(50)

b = sin(62)*4/sin(50)

b = 4.61042489526572

b = 4.6

Make sure your calculator is in degree mode.

8 0
3 years ago
Thomas goes to summer camp every year if his parents drive 155 miles to Camp to drop him off and then go back to pick him up in
prisoha [69]
I would say 465 since they go back and forth twice which is 155 x 3
8 0
2 years ago
Find the cube roots of 125(cos 288° + i sin 288°)
kow [346]
Let r(cos O + i sin O)  be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3  =  125(cos 288 + i sin 28)

so r^3 = 125  and  cos 3O + i sin 3O  =  cos 288 + i sin 288

so r  = 5  and 3O = 288 + 360p and O = 96 +  120p

so one cube root is   5 (cos 96 + i sin 96)

Im a little rusty at this stuff Its been a long time.

Im not sure of the other 2 roots

sorry cant help you any more


3 0
3 years ago
Read 2 more answers
Find the sum 7,388 and 829
FinnZ [79.3K]
8217 I think but I'm not sure
7 0
3 years ago
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