1 to 2 m tall please forgive meh
Answer: The habitat quality score will be normally distributed if at least 50% of the total sites are captured
Step-by-step explanation:
Answer:
38%
Step-by-step explanation:
Given that X,the hours per week the music student practice follow a normal distribution.
X:N(8,4)
We have to find the percentage of students who practice between 6 and 10 hours.
6<x<10 implies converting to z
We know z = (x-mean)/sigma = (x-8)/4
Hence 6<x<10 is equivalent to (6-8/4)<Z<(10-8/4)
= |z|<0.5
From std normal table we find this area equals = 0.1915+0.1915
=0.3830 = 0.38 (rounded off)
Hence required percentage = 0.38x100 = 38%
Answer:
199ft2
Step-by-step explanation:
area) H*W
(16ft×20ft)-(11ft×11ft)
=320ft2-121ft2
<h3>=199ft2</h3>
<em>ft</em><em> </em><em>square</em><em> </em><em>=</em><em>ft</em><em>2</em>
The slope would be letter b
