1. your leading coefficient has to be 1 (nothing before the x^2). If there is you have to divide that out before you start.
2. Move your constant (the number without any x attached) to the other side of the equation
3. take 1/2 of the b term (the one with the x attached) and then square it and then add it to both sides
4. Factor the left side
5. Set each factor equal to 0 and solve
Here is an example:
4x^2-24x+20=0
The first term is not a 1 so we have to divide it out by 4 first
x^2-6x+5=0
Move the 5 to the other side. It becomes negative.
x^2-6x=-5
Take 1/2 of 6 (3) then square it (9) and add it to both sides.
x^2-6x+9=-5+9
Factor the left side
(x-3)(x-3)=4
(x-3)^2=4
To solve you need to square root both sides
x-3=+/-
x-3=+/-2
x=3+2=5
x=3-2=1
Those would be your two answers.
<span>Hope that helps</span>
Answer
s = 11
Step-by-step explanation:
Find the value of S:
57 + s = 68
Substract 57 from both sides of the equation
s = 68 - 57
s = 11
Answer: y = 5y - (-2) < 17 =5y + 16
Answer:
1) 3.75
2)0.833333
3)3.66666
Step-by-step explanation:
See photo for Step-bystep explanation
Given:
A regular polygon with three vertices and side 14 cm.
To find:
Area of the regular polygon.
Solution:
We know that, a regular polygon has equal sides and equal interior angles.
The given regular polygon has three equal sides, it means it is an equilateral triangle.
The area of an equilateral triangle is:
Where, a is the side length of the triangle.
Putting 
, we get
Therefore, the area of given regular polygon is 84.9 cm².
