Find the equation for the inverse of the relation Y=2x+1
1 answer:
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Answer: 2676
Step-by-step explanation:
223 x 12 = 2676
This is because 223 12 times equals 2676.
*I will attach my work for the problem so you can see the solving process more clearly :).
Hope this helps :).
If the shape on the red image is scaled to the shape on the blue image, the scale factor is 0.2777.
Explanation:
- The original shape's base in the red image is measured. The base of the red image is measured to be 9 units. Now we measure the same side of the blue image. The base of the blue image is measured to be 2.5 units. So after scaling, the length of the painting will be 2.5 units.
- To calculate the scale factor, we divide the measurement after scaling by the same measurement before scaling. In this case, it is the base of both images. So The scale factor =
=
= 0.2777.
- So the red image is dilated by a scale factor of 0.2777 to produce the blue image.
The maximum error in the calculated surface area is 24.19cm² and the relative error is 0.0132.
Given that the circumference of a sphere is 76cm and error is 0.5cm.
The formula of the surface area of a sphere is A=4πr².
Differentiate both sides with respect to r and get
dA÷dr=2×4πr
dA÷dr=8πr
dA=8πr×dr
The circumference of a sphere is C=2πr.
From above the find the value of r is
r=C÷(2π)
By using the error in circumference relation to error in radius by:
Differentiate both sides with respect to r as
dr÷dr=dC÷(2πdr)
1=dC÷(2πdr)
dr=dC÷(2π)
The maximum error in surface area is simplified as:
Substitute the value of dr in dA as
dA=8πr×(dC÷(2π))
Cancel π from both numerator and denominator and simplify it
dA=4rdC
Substitute the value of r=C÷(2π) in above and get
dA=4dC×(C÷2π)
dA=(2CdC)÷π
Here, C=76cm and dC=0.5cm.
Substitute this in above as
dA=(2×76×0.5)÷π
dA=76÷π
dA=24.19cm².
Find relative error as the relative error is between the value of the Area and the maximum error, therefore:
As above its found that r=C÷(2π) and r=dC÷(2π).
Substitute this in the above
Hence, the maximum error in the calculated surface area with the circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm is 24.19cm² and the relative error is 0.0132.
Learn about relative error from here brainly.com/question/13106593
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