Find the equation for the inverse of the relation <br> Y=2x+1

lisov135 [29]

-4x +36 I am pretty sure

3 0

3 years ago

the figure below to answer the questions that follow 6cm LO 3.3.1 Calculate the angle, 60, in radians. (2) 3.3.2 Calculate the a

Mrrafil [7]

Answer:

it's very hard

im sorry dunno

3 0

3 years ago

Jordan Pat 6 4/5 yards of pink ribbon and 3 1/4 yards of purple ribbon how much more pink ribbon the purple ribbon did she buy?

evablogger [386]

Hello! For this question, we will have to subtract fractions. In order to do this, we will have to convert the fractions into the same denominator. We do this by finding the LCD of the two numbers. In other words, we find the LCM. The LCM of 5 and 4 is 20. 4/5 converts to 16/20, and 1/4 converts to 5/20. Let's subtract these numbers like we would regular numbers. 6 16/20 - 3 5/20 is 3 11/20. There. Jordan bought 3 11/20 yards more pink ribbon than purple ribbon.

8 0

3 years ago

To make a specific orange color, a painter uses 14 of a can of red paint and 12 of a can of yellow paint. Fill in each statement

Otrada [13]

Answer: For every 1 can of red paint, the number of yellow paints used by the painter is $\frac{6}{7}$ and

There are approximately 29 cans of yellow paints for 34 cans of red paints.

Step-by-step explanation:

Since we have given that

Number of cans of red paint = 14

Number of cans of yellow paint = 12

According to question, we have to find that for every 1 can of red paint the painter uses what number of yellow paints;

Since the ratio of red paint to yellow paint is given by

$14:12\\\\7:6\\\\1:\frac{6}{7}$

So, for every 1 can of red paint, the number of yellow paints used by the painter is $\frac{6}{7}$

Similarly,

If Number of can of red paint is used = 34

So, Number of cans of yellow paint will be

$\frac{6}{7}\times 34\\\\=\frac{6\times 34}{7}\\\\=29\ approx.$

Hence, there are approximately 29 cans of yellow paints for 34 cans of red paints.

3 0

3 years ago

The n candidates for a job have been ranked 1, 2, 3,…, n. Let X 5 the rank of a randomly selected candidate, so that X has pmf p

Anon25 [30]

Answer:

A. E(x) = 1/n×n(n+1)/2

B. E(x²) = 1/n

Step-by-step explanation:

The n candidates for a job have been ranked 1,2,3....n. Let x be the rank of a randomly selected candidate. Therefore, the PMF of X is given as

P(x) = {1/n, x = 1,2...n}

Therefore,

Expectation of X

E(x) = summation {xP(×)}

= summation {X×1/n}

= 1/n summation{x}

= 1/n×n(n+1)/2

= n+1/2

Thus, E(x) = 1/n×n(n+1)/2

Value of E(x²)

E(x²) = summation {x²P(×)}

= summation{x²×1/n}

= 1/n

3 0

3 years ago

Find the equation for the inverse of the relation Y=2x+1