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3 years ago

What is the equation of the line containing (4,-2) , (6,4)

Mathematics

2 answers:

AnnyKZ [126]3 years ago

4 0

4,12 , 6,4 containing

Radda [10]3 years ago

3 0

Answer:

Step-by-step explanation:

To find the slope it is: change in y/change in x

y_1 - y_2/x_1 - x_2. It can also be the variable sub 2, minus sub 1.

For this it is:

-2-4/4-6

-6/-2

m = 3

Slope intercept form is y = mx+b. Now we can sub in m. y = 3x+b.

To find b, sub in numbers from one of the points for x and y. I'm going to use (4,-2). Since in this case, -2 = y, and 4 = x, then those are the numbers I'm going to replace x and y with.

-2 = 3(4) +b

-2 = 12+b

-14=b

If -14 = b, and 3 = m, then your equation is y = 3x-14

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One of the factory’s profits over time can be modeled with the polynomial p(x)=2x6+123.5x4+389x2−25x5−304.75x3−237.25x+53.5.

Anettt [7]

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3 years ago

1. The diagonal of a quadrilateral

zalisa [80]

Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.

Given:

Length of the diagonal of a quadrilateral = 8.5 cm

Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.

To find:

The area of the quadrilateral.

Solution:

Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.

According to the question,

Triangle 1 : Base = 8.5 cm and Height = 3.5 cm

Triangle 2 : Base = 8.5 cm and Height = 4.5 cm

Area of a triangle is

$Area=\dfrac{1}{2}\times base \times height$

Using this formula, we get

$Area(\Delta 1)=\dfrac{1}{2}\times 8.5\times 3.5$

$Area(\Delta 1)=14.875$

and

$Area(\Delta 2)=\dfrac{1}{2}\times 8.5\times 4.5$

$Area(\Delta 2)=19.125$

Now, area of the quadrilateral is

$Area=Area(\Delta 1)+Area(\Delta 2)$

$Area=14.875+19.125$

$Area=34$

Therefore, the area of the quadrilateral is 34 cm².

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