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strojnjashka [21]
3 years ago
8

Solve for x. 4(3x-8)=-92 i need help

Mathematics
2 answers:
STALIN [3.7K]3 years ago
6 0

Answer:

x = -5

Step-by-step explanation:

Divide each term by 4 and simplify.

3x - 8 = -92

Move all terms not containing X to the right side of the equation.

3x = -15

Divide each term by 3 and simplify.

x=-5

lilavasa [31]3 years ago
3 0

Answer: x = -5.67

Step-by-step explanation:

Given the question, 4(3x-8)=-92, solve for x

First, we open the bracket

4×3x - 4×8 = - 92

12x - 24 = -92

Make x the subject by adding 24 to both sides

12x - 24 + 24 = -92 +24

12x = -68

Divide both sides by 12

x = -68/12

x = -5.67

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need helpA triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(
iogann1982 [59]

Answer:

2.5

Step-by-step explanation:

The dilation is 2.5. Using the point b(0,4) and B' (0,10), divide 10/4 you get 2.5.

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3 years ago
The Wall Street Journal reports that 33% of taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deduction
Len [333]

Answer:

(a) <em>                             </em><em>n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b) The correct option is (b).

Step-by-step explanation:

Let the random variable <em>X</em> represent the amount of deductions for taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return.

The mean amount of deductions is, <em>μ</em> = $16,642 and standard deviation is, <em>σ</em> = $2,400.

Assuming that the random variable <em>X </em>follows a normal distribution.

(a)

Compute the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $200 of the population mean as follows:

  • For a sample size of <em>n</em> = 20

P(\mu-200

                                           =P(-0.37

  • For a sample size of <em>n</em> = 50

P(\mu-200

                                           =P(-0.59

  • For a sample size of <em>n</em> = 100

P(\mu-200

                                           =P(-0.83

  • For a sample size of <em>n</em> = 500

P(\mu-200

                                           =P(-1.86

<em>                                  n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b)

The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample (\bar x) approaches the whole population mean (\mu_{x}).

Consider the probabilities computed in part (a).

As the sample size increases from 20 to 500 the probability that the sample mean is within $200 of the population mean gets closer to 1.

So, a larger sample increases the probability that the sample mean will be within a specified distance of the population mean.

Thus, the correct option is (b).

8 0
3 years ago
What is the value of (-140 ^0) ^ -2​
BigorU [14]
The answer is 1 because anything Raised to the power of zero will always be one in one to the power of -2 will be one
7 0
3 years ago
Read 2 more answers
21 is 42% of what number
Step2247 [10]
21 is 42% of 50 , So the correct answer is 50
4 0
3 years ago
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