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Zarrin [17]
3 years ago
15

A bison herd has decreased 10% in population this year compared to last year. If there are 550 bison this year, how many were th

ere last year?​
Mathematics
2 answers:
Alex3 years ago
8 0

Answer:

Step-by-step explanation:

Herd decreased 10% and there is now 550.

Multiply the total by 110% or multiply the total by 10% and add that to the 550 total.

550*1.1=605 bison. Or 550*.1 + 550 = 55 +550 = 605 bison.

allsm [11]3 years ago
4 0

Answer: 605

Step-by-step explanation:

This year Last year

550 x 1.1 = 605

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3 years ago
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Which of the following lines is perpendicular to the equation given below?
konstantin123 [22]

Answer:

C

Step-by-step explanation:

x+2y=8x...............

4 0
3 years ago
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(b) Find all 3-tuples (a,b,c) satisfying
jolli1 [7]

We have a three unknown, 4 equation homogeneous system.  These always have at least (0,0,0) as a solution.  Let's write the equations, one column at a time.

1a + 0b + 0c = 0

-1a + 1b +0c = 0

0a - 1b + c = 0

0a + 0b + -1 c = 0

We could do row reduction but these are easy enough not to bother.

Equation 1 says

a = 0

Equation 4 says

c = 0

Substituting in the two remaining,

-1(0) + 1b + 0c = 0

b = 0

0(0) - 1b + 0 = 0

b = 0

The only 3-tuple satisfying the vector equation is (a,b,c)=(0,0,0)

4 0
3 years ago
Which value of x from the set {5, 6, 7, 8} makes this equation true? 3x = 24
Tju [1.3M]

Answer:

Value x = 8 make the equation true .

Step-by-step explanation:

Given  : 3x = 24.

To find : Which value of x from the set {5, 6, 7, 8} makes this equation true?

Solution : We have given 3x = 24.

The equations are true when the Left hand side and right hand side of the equation are equal.

Then,

For x = 8 .

3 ( 8) = 24

24 = 24 .

Hence,

Left hand side = Right hand side.

Therefore, Value x = 8 make the equation true .

3 0
3 years ago
5. Show that the following points are collinear. a) (1, 2), (4, 5), (8,9) ​
Irina-Kira [14]

Label the points A,B,C

  • A = (1,2)
  • B = (4,5)
  • C = (8,9)

Let's find the distance from A to B, aka find the length of segment AB.

We use the distance formula.

A = (x_1,y_1) = (1,2) \text{ and } B = (x_2, y_2) = (4,5)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (2-5)^2}\\\\d = \sqrt{(-3)^2 + (-3)^2}\\\\d = \sqrt{9 + 9}\\\\d = \sqrt{18}\\\\d = \sqrt{9*2}\\\\d = \sqrt{9}*\sqrt{2}\\\\d = 3\sqrt{2}\\\\

Segment AB is exactly 3\sqrt{2} units long.

Now let's find the distance from B to C

B = (x_1,y_1) = (4,5) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(4-8)^2 + (5-9)^2}\\\\d = \sqrt{(-4)^2 + (-4)^2}\\\\d = \sqrt{16 + 16}\\\\d = \sqrt{32}\\\\d = \sqrt{16*2}\\\\d = \sqrt{16}*\sqrt{2}\\\\d = 4\sqrt{2}\\\\

Segment BC is exactly 4\sqrt{2} units long.

Adding these segments gives

AB+BC = 3\sqrt{2}+4\sqrt{2} = 7\sqrt{2}

----------------------

Now if A,B,C are collinear then AB+BC should get the length of AC.

AB+BC = AC

Let's calculate the distance from A to C

A = (x_1,y_1) = (1,2) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-8)^2 + (2-9)^2}\\\\d = \sqrt{(-7)^2 + (-7)^2}\\\\d = \sqrt{49 + 49}\\\\d = \sqrt{98}\\\\d = \sqrt{49*2}\\\\d = \sqrt{49}*\sqrt{2}\\\\d = 7\sqrt{2}\\\\

AC is exactly 7\sqrt{2} units long.

Therefore, we've shown that AB+BC = AC is a true equation.

This proves that A,B,C are collinear.

For more information, check out the segment addition postulate.

7 0
3 years ago
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