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serious [3.7K]
3 years ago
14

Finding the circumference, PLEASE HELP :C Ill give brainliest! 20 points!

Mathematics
2 answers:
Setler79 [48]3 years ago
6 0

Answer:

d=7925mi

circumference of circle=πd

=3.14×7925

=24884.5 mi

kogti [31]3 years ago
4 0

Answer:

24, 897.12178 mi

Step-by-step explanation:

diameter is 7,925 mi

circumference = diameter *pi = 7,925*3.14= 24, 897.12178 mi

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Tanikwa started a new exercise program using the indoor track. In her first workout she ran 8 laps for every 4 laps that she wal
Elina [12.6K]

Answer:

The correct answer would be 2:1

Step-by-step explanation:

In order to find this, start with the ratio as it is written and sub in the values. Then simplify to the lowest possible terms.

Ran:Walker

8:4

2:1

6 0
3 years ago
Find the indicated probability.
natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

<u>Recall:</u>

  • Binomial Distribution --> P(k)={n\choose k}p^kq^{n-k}
  • P(k) denotes the probability of k successes in n independent trials
  • p^k denotes the probability of success on each of k trials
  • q^{n-k} denotes the probability of failure on the remaining n-k trials
  • {n\choose k}=\frac{n!}{(n-k)!k!} denotes all possible ways to choose k things out of n things

<u>Given:</u>

  • n=10
  • k=4
  • p^k=0.53^4
  • q^{n-k}=(1-0.53)^{10-4}=0.47^6
  • {n\choose k}={10\choose 4}=\frac{10!}{(10-4)!4!}=210

<u>Calculate:</u>

  • P(4)=(210)(0.53^4)(0.47^6)=0.1786117069\approx0.179

Therefore, the probability that the archer will get exactly 4 bull's-eyes with 10 arrows in any order is 0.179

7 0
2 years ago
An ice-skating rink hosts different events on different days of the week they keep track of ages of the people who attended the
kirill [66]

Answer:

i think it is B

Step-by-step explanation:

4 0
3 years ago
WILL MARK BRAINLIEST! PLEASE HELP!<br> Write 206 in base 7
Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!\(\*SuperscriptBox[\(Base\), \(Power\)]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

5 0
2 years ago
Melanie draws with great fervor, using up pencils at an incredible rate: 14 pencils every
AfilCa [17]
4 pencils . 4/9 of an hour = 4/9 of 60 minutes = 4/9 * 60 = 80/3 minutes
x pencils = ? . one hour = 60 minutes

14 * 60 = 80/3 * x       /*3
14 * 60 * 3 = 80 * x
80 * x = 2520            /80
x = 2520 / 80
x = 31.5 pencils

The result would be 32 pencils in one hour.
5 0
3 years ago
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