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Lorico [155]
3 years ago
5

Match each equation on the left to the mathematical property it uses on the right

Mathematics
1 answer:
Degger [83]3 years ago
3 0

Answer:

attachment plz

Step-by-step explanation:

nothing is being seen

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A poll asked 15 men in two age groups, 30 and younger and older than 30, whether they had facial hair (mustache, beard, sideburn
Cloud [144]

Answer:

                                 ------ Facial hair ------

                                Yes         No         Total

Age    

30 and younger       0.267     0.200   0.467

older than 30           0.333     0.200    0.533

Total                         0.600     0.400    1.000

Step-by-step explanation:

1.  Count the number of people for each category:

<u>a) People who were 30 and younger and had facial hair:</u>

  • 1: 30 and younger. Yes
  • 9: 30 and younger. Yes
  • 10: 30 and younger. Yes
  • 12: 30 and younger. Yes

<em>Total: 4 people were 30 and younger and had facial hair</em>

<em />

<u>b) People who were 30 and younger and did not have facial hair</u>:

  • 2: 30 and younger.No
  • 4: 30 and younger. No
  • 14: 30 and younger. No

<em>Total: 3 people were 30 and younger and did not have facial hair</em>

<u />

<u>c) People who were older than 30 and had facial hair</u>:

  • 6: Older than 30. Yes
  • 7: Older than 30.Yes
  • 11: Older than 30. Yes
  • 13: Older than 30. Yes
  • 15: Older than 30. Yes

<em>Total: 5 people were older than 30 and had facial hair</em>.

<u />

<u>d) People who were older than 30 and did not have facial hair:</u>

  • 3: Older than 30. No
  • 5: Older than 30. No
  • 8: Older than 30. No

<em>Total: 3 people were older than 30 and did not have facial hair</em>.

2. Build a two way table with the absolute frequencies:

                               ------ Facial hair ------

                                Yes         No     Total

Age    

30 and younger       4               3          7

older than 30           5               3          8

Total                         9               6         15

3. To build the two-way relative frequency table, divive each absolute frequency by the total number of men (15):

These are the quotients:

  • 4/15 = 0.267
  • 3/15 = 0.200
  • 7/15 = 0.467
  • 5/15 = 0.333
  • 3/15 = 0.200
  • 8/15 = 0.533
  • 9/15 = 0.600
  • 6/15 = 0.400
  • 15/15 = 1.000

Now write the table with the relative frequencies:

                               -------- Facial hair --------

                                Yes         No         Total

Age    

30 and younger       0.267     0.200   0.467

older than 30           0.333     0.200    0.533

Total                         0.600     0.400    1.000

And that is the requested <em>table written to three decimal places</em>.

6 0
3 years ago
30 points! Look at pic attached, Will mark brainliest!!!
den301095 [7]

Answer:

what

Step-by-step explanation:

what

3 0
3 years ago
Can a triangle with side lengths 7, 25, and 19 be a right triangle?
NARA [144]

Well, the Pythagorean theorem is helpful.

Does 7^2+19^2=25^2?

no it desn't, so no it is not a right triangle

7 0
3 years ago
(Step to step work)<br><br> sin x(cotx + tanx)
11Alexandr11 [23.1K]

solving sin(x)(cot(x) + tan(x)) we get sec(x)

Step-by-step explanation:

We need to solve: sin(x)(cot(x) + tan(x))

Solving:

We know:

cot(x)=\frac{cos(x)}{sin(x)}\\ and\,\,tan(x)=\frac{sin(x)}{cos(x)}

Putting the values of cot(x) and tan(x):

sin(x)(cot(x) + tan(x))\\=sin(x)(\frac{cos(x)}{sin(x)}+\frac{sin(x)}{cos(x)})

Taking LCM:

=sin(x)(\frac{cos(x)cos(x)+sin(x)sin(x)}{sin(x)cos(x)})\\=sin(x)(\frac{cos^2(x)+sin^2(x)}{sin(x)cos(x)})

We know that: cos^2x+sin^2x=1

and using identity: cos(x)sin(x)=sin(2x)*1/2

=sin(x)(\frac{1}{sin(2x)\frac{1}{2}})\\=sin(x)(\frac{2}{sin(2x)})

Using identity: sin(2x)=2cos(x)sin(x)

=sin(x)(\frac{2}{2sin(x)cos(x)})\\Cancelling\,\,same\,\,terms\,\,in\,\,numerator\,\,and\,\,denominator:\\=\frac{1}{cos(x)} \\=sec(x)

So, solving sin(x)(cot(x) + tan(x)) we get sec(x)

Keywords: Trigonometry

Learn more about Trigonometry at:

  • brainly.com/question/13219835
  • brainly.com/question/5013374
  • brainly.com/question/9532142

#learnwithBrainly

8 0
3 years ago
Pt 2 . This is my last one I need helppp!:(
Veseljchak [2.6K]
<h2>c = 10b</h2><h3 /><h3><em>Please let me know if I am wrong.</em></h3>
4 0
3 years ago
Read 2 more answers
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