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nekit [7.7K]
3 years ago
8

A bowl contains blueberries and strawberries. There are a total of 16 berries in the bowl. The ratio of blueberries to strawberr

ies is 3 : 1. How many of each berry are in the bowl?
Mathematics
1 answer:
mestny [16]3 years ago
5 0

Answer:

12 blueberries and 4 strawberries

Step-by-step explanation:

We can try the guess method.

3:1      3 + 1 = 4     4 is too low. We need a sum of 16.

Multiply both numbers in the ratio by 2.

6:2     6 + 2 = 8   8 is still too low

Multiply both numbers in the ratio by 4.

12:4    12 + 4 = 16    16 is correct.

Answer: 12 blueberries and 4 strawberries

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Fill in the blanks in the following proof.
NARA [144]

Answer:

Table :

     Statements                 Reasons

1)ΔEGC≅ΔEGB                 Given

2)EB = EC                          Corresponding Parts of Congruent

                                          Triangles are Congruent

3) BC = BE                         Given

4) By 2 and 3                      EB≅EC≅BC

5)∠BEC = 60°                     ΔBEC is an equilateral triangle

Step-by-step explanation:

We are given that BE = BC  ---1

We are also given that ΔEGC≅ΔEGB

So, BE = CE(Corresponding Parts of Congruent Triangles are Congruent) ---2

Now By 1 and 2

BE=BC=CE

In ΔBEC

BE=BC=CE

Since all sides are equal . So, it is an equilateral triangle

All angles of equilateral triangle are also equal i.e. 60°

So, ∠BEC = 60°

Hence proved

Table :

     Statements                 Reasons

1)ΔEGC≅ΔEGB                 Given

2)EB = EC                          Corresponding Parts of Congruent

                                          Triangles are Congruent

3) BC = BE                         Given

4) By 2 and 3                      EB≅EC≅BC

5)∠BEC = 60°                     ΔBEC is an equilateral triangle

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Step-by-step explanation:

B=100e^{0.592t}

c) To solve for t, take the natural logarithm of the above equation:

\dfrac{B}{100}=e^{0.592t}

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Recall that \ln e = 1 so we can rewrite the equation above as

0.592t = \ln \left(\dfrac{B}{100} \right)

Finally, solving for t, we get

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