Answer:
Third sequence (7, 2, 1, -4, -10)
In the first sequence, -4 has to be in front of -10 because it is larger.
In the second sequence, 7 goes in the beginning, with 2 then 1 following, with -4 behind and -10 behind -4.
In the third option, 7 must be in the front, with 2, 1, then -4, then -10 following.
The answer = third sequence.
Hope it helped!
Answer:
-11/20
Step-by-step explanation:
2 8 1
(0-— ÷ (0-—))+—
3 9 5
8
Simplify —
8/9
2 8 1
(0 - — ÷ (0 - —)) + —
3 9 5
Simplify —
2/3
2 -8 1
(0 - — ÷ ——) + —
3 9 5
2 -8
Divide — by ——
3 9
To divide fractions, write the divison as multiplication by the reciprocal of the divisor :
2 -8 2 9
— ÷ —— = — • ——
3 9 3 -8
(0--3/4)+1/5
Least Common Multiple:
20
Left_M = L.C.M / L_Deno = 5
Right_M = L.C.M / R_Deno = 4
3 • 5 + 4 -11
————————— = ———
20 20
-11/20
Answer:
Survey
Step-by-step explanation: A survey is a research method of collecting data from a particular target group through questions aimed at extracting specific information from them
If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
