Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />
The answer is negative 1. This is because the sequence follows a pattern of the final number being 4, then 9, then 4 again. near the end of the sequence, you will end at the term of positive 4, which when 5 is subtracted from it (the pattern is -5), the first negative term is -1.
Here, what you would do is combine like terms. So you get P+2q.
Answer:5.48 days
Step-by-step explanation:
Given
Initial amount of bacteria 
Final Population of bacteria 
Using formula
where T=time in days
Taking log both side
Answer:
<h2><E</h2>
Step-by-step explanation:
<E is larger than <B
hope it helps
