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4 years ago

If somebody could help quickly that would be amazing. Solve for a: 5 a - 2 = 23 a =

Mathematics

2 answers:

Readme [11.4K]4 years ago

7 0

Answer:

$a = - \frac{1}{9}$

Step-by-step explanation:

$5a - 2 = 23a$

Collect like terms and simplify

$- 2 = 23a - 5a \\ - 2 = 18a$

Divide both sides of the equation by 18 and simplify

$\frac{ - 2}{18} = \frac{18a}{18} \\ - \frac{1}{9} = a$

ad-work [718]4 years ago

3 0

Answer:

answer. -9

Step-by-step explanation:

5a-2=23a

5a-23a=2

-18a=2

a=-18/2

a=-9

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The equation P=6s represents the perimeter P of a regular hexagon with side length s. What is the perimeter of a regular hexagon

Verdich [7]

we know that s = 3, so plug it in.

P = 6(3)

P = 18

perimeter = 18 km

6 0

3 years ago

Read 2 more answers

At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us

wolverine [178]

Answer:

<u>The expected value of every ticket is a loss of $ 1.35</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

Probability of 1st prize of $ 498 (500 - ticket) = 1/1,500
Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
Probability of 3rd prize of $ 148 (150 - ticket) = 1/1,500
Probability of 4th prize of $ 73 (75 - ticket) = 1/1,500
Probability of losing $ 2 (ticket) = 1,496/1,500

Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

Expected value = [- 2,992 +498 + 248 + 148 + 73)/1,500

Expected value = -2,025/1,500 = - 1,35

<u>The expected value of every ticket is a loss of $ 1.35</u>

8 0

4 years ago

How many integers between 100 and 1000 have both 15 and 18 as factors?

Zanzabum

The numbers 180, 270, 360, 450, 540, 630, 720, 810, and 900 are the integers between 100 and 1000 that have both 15 and 18 as a factor.

<h3>What is an integer?</h3>

it is defined as the whole number it can be a negative whole number or a positive whole number for an example: 2, 4, 1, -8, 0, etc.

To find the how many integers between 100 and 1000 have both 15 and 18 as factors.

We must calculate the LCM of 15 and 18

The LCM for 15 and 18 is 90

Now the 90's multiple:

90, 180, 270, 360, 450, 540, 630, 720, 810, 900, 1080

These numbers are factors of 15 and 18 also.

The number which lies between 100 and 1000 are:

180, 270, 360, 450, 540, 630, 720, 810, 900

Thus, the numbers 180, 270, 360, 450, 540, 630, 720, 810, and 900 are the integers between 100 and 1000 that have both 15 and 18 as a factor.

Learn more about the integers here:

here:brainly.com/question/15276410

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4 0

2 years ago

Jaclyn is a soccer goalie. If she has 21 out of 25 saves in practice, what is the experimental probability that she will have a

horsena [70]

Answer:

Im a soccer goalie too

Step-by-step explanation: 21/25, 0.84, 84%

8 0

3 years ago