- An eagle and a grizzly bear both feed on the same
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Answer: Hello your question some missing data attached below is the complete question
answer:
P( first child having PKU ) 0.25 ≤ x ≤ 0.5
Explanation:
The pedigree father has PKU ( pp ) ( From the top right )
pedigree mother = PP
The possible resultant progeny = Pp
Resultant progeny marries non-carrier ( Pp x PP ) = PP , PP, pP, pP
Hence B is either ; PP ( non carrier ) or Pp ( carrier )
<em>From left</em>
one of the Resultant progeny = pp ( affected ). this simply means pedigree parents where both carriers or sufferers i.e. Pp or pp
Hence A is either ; Pp or pp
The probability of their first child having PKU
= PP x Pp = PP, Pp, PP, Pp ( probability = 0 in this case )
= Pp x Pp = PP, Pp, pP, pp ( probability = 1/4 * 100 = 25% )
= Pp x pp = Pp, Pp, pp, pp ( probability = 2/4 * 100 = 50% )
P( first child having PKU ) 0.25 ≤ x ≤ 0.5
lets denote dominant Gene = PP, recessive Gene = pp
